Why is __code__ for a function(Python) mutable

问题

In a previous question yesterday, in comments, I came to know that in python __code__ atrribute of a function is mutable. Hence I can write code as following

def foo():
    print "Hello"

def foo2():
    print "Hello 2"

foo()
foo.__code__ = foo2.__code__
foo()

Output

Hello
Hello 2

I tried googling, but either because there is no information(I highly doubt this), or the keyword (__code__) is not easily searchable, I couldn't find a use case for this.

It doesn't seem like "because most things in Python are mutable" is a reasonable answer either, because other attributes of functions — __closure__ and __globals__ — are explicitly read-only (from Objects/funcobject.c):

static PyMemberDef func_memberlist[] = {
    {"__closure__",   T_OBJECT,     OFF(func_closure),
     RESTRICTED|READONLY},
    {"__doc__",       T_OBJECT,     OFF(func_doc), PY_WRITE_RESTRICTED},
    {"__globals__",   T_OBJECT,     OFF(func_globals),
     RESTRICTED|READONLY},
    {"__module__",    T_OBJECT,     OFF(func_module), PY_WRITE_RESTRICTED},
    {NULL}  /* Sentinel */
};

Why would __code__ be writable while other attributes are read-only?

回答1:

The fact is, most things in Python are mutable. So the real question is, why are __closure__ and __globals__ not?

The answer initially appears simple. Both of these things are containers for variables which the function might need. The code object itself does not carry its closed-over and global variables around with it; it merely knows how to get them from the function. It grabs the actual values out of these two attributes when the function is called.

But the scopes themselves are mutable, so this answer is unsatisfying. We need to explain why modifying these things in particular would break stuff.

For __closure__, we can look to its structure. It is not a mapping, but a tuple of cells. It doesn't know the names of the closed-over variables. When the code object looks up a closed-over variable, it needs to know its position in the tuple; they match up one-to-one with co_freevars which is also read-only. And if the tuple is of the wrong size or not a tuple at all, this mechanism breaks down, probably violently (read: segfaults) if the underlying C code isn't expecting such a situation. Forcing the C code to check the type and size of the tuple is needless busy-work which can be eliminated by making the attribute read-only. If you try to replace __code__ with something taking a different number of free variables, you get an error, so the size is always right.

For __globals__, the explanation is less immediately obvious, but I'll speculate. The scope lookup mechanism expects to have access to the global namespace at all times. Indeed, the bytecode may be hard-coded to go straight to the global namespace, if the compiler can prove no other namespace will have a variable with a particular name. If the global namespace was suddenly None or some other non-mapping object, the C code could, once again, violently misbehave. Again, making the code perform needless type checks would be a waste of CPU cycles.

Another possibility is that (normally-declared) functions borrow a reference to the module's global namespace, and making the attribute writable would cause the reference count to get messed up. I could imagine this design, but I'm not really sure it's a great idea since functions can be constructed explicitly with objects whose lifetimes might be shorter than that of the owning module, and these would need to be special-cased.

来源：https://stackoverflow.com/questions/31599376/why-is-code-for-a-functionpython-mutable

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