add sender's name in the from field of the email in python

问题

I am trying to send email with below code.

import smtplib
from email.mime.text import MIMEText

sender = 'sender@sender.com'

def mail_me(cont, receiver):
    msg = MIMEText(cont, 'html')
    recipients = ",".join(receiver)
    msg['Subject'] = 'Test-email'
    msg['From'] = "XYZ ABC"
    msg['To'] = recipients
    # Send the message via our own SMTP server.
    try:
        s = smtplib.SMTP('localhost')
        s.sendmail(sender, receiver, msg.as_string())
        print "Successfully sent email"
    except SMTPException:
        print "Error: unable to send email"
    finally:
        s.quit()


cont = """\
   <html>
     <head></head>
     <body>
       <p>Hi!<br>
          How are you?<br>
          Here is the <a href="http://www.google.com">link</a> you wanted.
       </p>
     </body>
   </html>
   """
mail_me(cont,['xyz@xyzcom'])

I want "XYZ ABC" to appear as the sender's name when the email is received and its email address as 'sender@sender.com'. but when i receive email i am receiving weird details in "from" fields of the email message.

[![from:    XYZ@<machine-hostname-appearing-here>
reply-to:   XYZ@<machine-hostname-appearing-here>,
ABC@<machine-hostname-appearing-here>][1]][1]

I have attached a screenshot of the email that i receive.

how can i fix this according to my need.

回答1:

This should work:

msg['From'] = "Your name <Your email>"

Example below:

import smtplib
from email.mime.text import MIMEText

def send_email(to=['example@example.com'], f_host='example.example.com', 
f_port=587, f_user='example@example.com', f_passwd='example-pass', 
subject='default subject', message='content message'):
smtpserver = smtplib.SMTP(f_host, f_port)
smtpserver.ehlo()
smtpserver.starttls()
smtpserver.ehlo
smtpserver.login(f_user, f_passwd) # from email credential
msg = MIMEText(message, 'html')
msg['Subject'] = 'My custom Subject'
msg['From'] = "Your name <Your email>"
msg['To'] = ','.join(to)
for t in to:
    smtpserver.sendmail(f_user, t, msg.as_string())  # you just need to add 
this in for loop in your code.
    smtpserver.close()
print('Mail is sent successfully!!')


cont = """\
<html>
 <head></head>
 <body>
   <p>Hi!<br>
      How are you?<br>
      Here is the <a href="http://www.google.com">link</a> you wanted.
   </p>
 </body>
</html>
"""
try:
send_email(message=cont)
except:
print('Mail could not be sent')

回答2:

Just tested the following code with gmx.com and it works fine. Although, whether you get the same mileage is a moot point.
I have replaced all references to my email service with gmail

#!/usr/bin/python

#from smtplib import SMTP # Standard connection
from smtplib import SMTP_SSL as SMTP #SSL connection
from email.MIMEMultipart import MIMEMultipart
from email.MIMEText import MIMEText

sender = 'example@gmail.com'
receivers = ['example@gmail.com']


msg = MIMEMultipart()
msg['From'] = 'example@gmail.com'
msg['To'] = 'example@gmail.com'
msg['Subject'] = 'simple email via python test 1'
message = 'This is the body of the email line 1\nLine 2\nEnd'
msg.attach(MIMEText(message))

ServerConnect = False
try:
    smtp_server = SMTP('smtp.gmail.com','465')
    smtp_server.login('#name#@gmail.com', '#password#')
    ServerConnect = True
except SMTPHeloError as e:
    print "Server did not reply"
except SMTPAuthenticationError as e:
    print "Incorrect username/password combination"
except SMTPException as e:
    print "Authentication failed"

if ServerConnect == True:
    try:
        smtp_server.sendmail(sender, receivers, msg.as_string())
        print "Successfully sent email"
    except SMTPException as e:
        print "Error: unable to send email", e
    finally:
        smtp_server.close()

回答3:

This should fix it:

Replace mail_me(cont,['xyz@xyzcom']) with

mail_me(cont,'xyz@xyz.com')

回答4:

The name comes from the FROM header. Refer to this answer please Specify a sender when sending mail with Python (smtplib)

回答5:

A space is not a valid character in an email address. Special characters are only allowed in the external representation that shall be enclosed in double quotes. Additionaly, most SMTP servers actually use header rewriting to ensure that addresses are in standard format. As yours actually contains a space it is splitted and as it is not enclosed in quotes, the server address is appended to it.

You have just to replace msg['From'] = "XYZ ABC" with

msg['From'] = '"XYZ ABC"'

forcing inclusion of the address in double quotes.

回答6:

import smtplib
from email.mime.text import MIMEText

def send_email(to=['example@example.com'], f_host='example.example.com', f_port=587, f_user='example@example.com', f_passwd='example-pass', subject='default subject', message='content message'):
    smtpserver = smtplib.SMTP(f_host, f_port)
    smtpserver.ehlo()
    smtpserver.starttls()
    smtpserver.ehlo
    smtpserver.login(f_user, f_passwd) # from email credential
    msg = MIMEText(message, 'html')
    msg['Subject'] = 'My custom Subject'
    msg['From'] = "Admin"
    msg['To'] = ','.join(to)
    for t in to:
        smtpserver.sendmail(f_user, t, msg.as_string())  # you just need to add this in for loop in your code.
        smtpserver.close()
    print('Mail is sent successfully!!')


cont = """\
   <html>
     <head></head>
     <body>
       <p>Hi!<br>
          How are you?<br>
          Here is the <a href="http://www.google.com">link</a> you wanted.
       </p>
     </body>
   </html>
   """
try:
    send_email(message=cont)
except:
    print('Mail could not be sent')

above method I have tried to send mail which is worked for me even I am able to send mail to my gmail account(in spam folder). Let me know if you face any other related problem.

来源：https://stackoverflow.com/questions/44385652/add-senders-name-in-the-from-field-of-the-email-in-python

标签

python

smtplib