Web Audio API append/concatenate different AudioBuffers and play them as one song

旧时模样 提交于 2019-11-27 10:52:31

问题


I've been playing with the Web Audio API and I'm trying to load multiple parts of a song and append them to a new ArrayBuffer and then use that ArrayBuffer for playing all the parts as one song. In the following example I am using the same song data (which is a small loop) instead of different parts of a song.

The problem is that it still plays just once instead of two times and I don't know why.

Download song

function init() {

  /**
   * Appends two ArrayBuffers into a new one.
   * 
   * @param {ArrayBuffer} buffer1 The first buffer.
   * @param {ArrayBuffer} buffer2 The second buffer.
   */
  function appendBuffer(buffer1, buffer2) {
    var tmp = new Uint8Array(buffer1.byteLength + buffer2.byteLength);
    tmp.set( new Uint8Array(buffer1), 0);
    tmp.set( new Uint8Array(buffer2), buffer1.byteLength);
    return tmp;
  }

  /**
   * Loads a song
   * 
   * @param {String} url The url of the song.
   */
  function loadSongWebAudioAPI(url) {
    var request = new XMLHttpRequest();
    var context = new webkitAudioContext();

    request.open('GET', url, true);
    request.responseType = 'arraybuffer';

    /**
     * Appends two ArrayBuffers into a new one.
     * 
     * @param {ArrayBuffer} data The ArrayBuffer that was loaded.
     */
    function play(data) {
      // Concatenate the two buffers into one.
      var a = appendBuffer(data, data);
      var buffer = a.buffer;
      var audioSource = context.createBufferSource();
      audioSource.connect(context.destination);

      //decode the loaded data
      context.decodeAudioData(buffer, function(buf) {
        console.log('The buffer', buf);
        audioSource.buffer = buf;
        audioSource.noteOn(0);
        audioSource.playbackRate.value = 1;
      });

    };

    // When the song is loaded asynchronously try to play it.
    request.onload = function() {
      play(request.response);
    }

    request.send();
  }


  loadSongWebAudioAPI('http://localhost:8282/loop.mp3');
}

window.addEventListener('load',init,false);

回答1:


The problem in your code is that you're copying and appending another copy of the MP3 file onto the end of itself. That copy gets effectively ignored by the decoder - it's not raw buffer data, it's just random spurious junk in the file stream, following a perfectly complete MP3 file.

What you need to do is first decode the audio data into a AudioBuffer, then append the audio buffers together into a new AudioBuffer. This requires a little bit of restructuring of your code.

What you want to do is this:

var context = new webkitAudioContext();

function init() {

  /**
   * Appends two ArrayBuffers into a new one.
   * 
   * @param {ArrayBuffer} buffer1 The first buffer.
   * @param {ArrayBuffer} buffer2 The second buffer.
   */
  function appendBuffer(buffer1, buffer2) {
    var numberOfChannels = Math.min( buffer1.numberOfChannels, buffer2.numberOfChannels );
    var tmp = context.createBuffer( numberOfChannels, (buffer1.length + buffer2.length), buffer1.sampleRate );
    for (var i=0; i<numberOfChannels; i++) {
      var channel = tmp.getChannelData(i);
      channel.set( buffer1.getChannelData(i), 0);
      channel.set( buffer2.getChannelData(i), buffer1.length);
    }
    return tmp;
  }

  /**
   * Loads a song
   * 
   * @param {String} url The url of the song.
   */
  function loadSongWebAudioAPI(url) {
    var request = new XMLHttpRequest();

    request.open('GET', url, true);
    request.responseType = 'arraybuffer';

    /**
     * Appends two ArrayBuffers into a new one.
     * 
     * @param {ArrayBuffer} data The ArrayBuffer that was loaded.
     */
    function play(data) {
      //decode the loaded data
      context.decodeAudioData(data, function(buf) {
        var audioSource = context.createBufferSource();
        audioSource.connect(context.destination);

        // Concatenate the two buffers into one.
        audioSource.buffer = appendBuffer(buf, buf);
        audioSource.noteOn(0);
        audioSource.playbackRate.value = 1;
      });

    };

    // When the song is loaded asynchronously try to play it.
    request.onload = function() {
      play(request.response);
    }

    request.send();
  }


  loadSongWebAudioAPI('loop.mp3');
}

window.addEventListener('load',init,false);

There's a slight playback gap - that's because you have nearly 50ms of silence at the beginning of your sound sample, not due to looping issues.

Hope this helps!




回答2:


If you need to append/concatenate a list of buffer from an array (not only 2), here is a solution. I have just tweaked a bit the @Cwilso code (thanks for your help ;)

function concatBuffer(_buffers) {
    // _buffers[] is an array containig our audiobuffer list

    var buflengh = _buffers.length;
    var channels = [];
    var totalDuration = 0;

    for(var a=0; a<buflengh; a++){
        channels.push(_buffers[a].numberOfChannels);// Store all number of channels to choose the lowest one after
        totalDuration += _buffers[a].duration;// Get the total duration of the new buffer when every buffer will be added/concatenated
    }

    var numberOfChannels = channels.reduce(function(a, b) { return Math.min(a, b); });;// The lowest value contained in the array channels
    var tmp = context.createBuffer(numberOfChannels, context.sampleRate * totalDuration, context.sampleRate);// Create new buffer

    for (var b=0; b<numberOfChannels; b++) {
        var channel = tmp.getChannelData(b);
        var dataIndex = 0;

        for(var c = 0; c < buflengh; c++) {
            channel.set(_buffers[c].getChannelData(b), dataIndex);
            dataIndex+=_buffers[c].length;// Next position where we should store the next buffer values
        }
    }
    return tmp;
}


来源:https://stackoverflow.com/questions/14143652/web-audio-api-append-concatenate-different-audiobuffers-and-play-them-as-one-son

易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!