问题
I have three points, for example:
Start 194 171
Right 216 131
Left 216 203
I want to get all the points within that triangle. How would I do that efficiently?
回答1:
see z3nth10n's answer for better input validation
Introduction:
The general idea was to get the triangle's edges (y-Wise) for every x in it's range, and then you have all the y's that exist within the triangle for every single x, which with simple conversion turns into all points within the triangle.
You can look at it as if you cut the triangle into stripes, each being of width 1. So for X=0, on the line between A and B, the Y is 6, and on the line between A and C, the Y is -2, so you can see that the stripe of X=0 is between -2 and 6. Therefore, you can tell that (0, -2) (0, -1) (0, 0) ... (0, 5) (0, 6) are all in the triangle. Doing that for X's between the smallest and the largest within the triangle, and you have all the points in the triangle!
Speed:
For the triangle (0, 0) (1, 8) (4, 6) - found 16 points.
Done 1,000,000 times in 3.68 seconds.
Implementation:
public IEnumerable<Point> PointsInTriangle(Point pt1, Point pt2, Point pt3)
{
if (pt1.Y == pt2.Y && pt1.Y == pt3.Y)
{
throw new ArgumentException("The given points must form a triangle.");
}
Point tmp;
if (pt2.X < pt1.X)
{
tmp = pt1;
pt1 = pt2;
pt2 = tmp;
}
if (pt3.X < pt2.X)
{
tmp = pt2;
pt2 = pt3;
pt3 = tmp;
if (pt2.X < pt1.X)
{
tmp = pt1;
pt1 = pt2;
pt2 = tmp;
}
}
var baseFunc = CreateFunc(pt1, pt3);
var line1Func = pt1.X == pt2.X ? (x => pt2.Y) : CreateFunc(pt1, pt2);
for (var x = pt1.X; x < pt2.X; x++)
{
int maxY;
int minY = GetRange(line1Func(x), baseFunc(x), out maxY);
for (var y = minY; y <= maxY; y++)
{
yield return new Point(x, y);
}
}
var line2Func = pt2.X == pt3.X ? (x => pt2.Y) : CreateFunc(pt2, pt3);
for (var x = pt2.X; x <= pt3.X; x++)
{
int maxY;
int minY = GetRange(line2Func(x), baseFunc(x), out maxY);
for (var y = minY; y <= maxY; y++)
{
yield return new Point(x, y);
}
}
}
private int GetRange(double y1, double y2, out int maxY)
{
if (y1 < y2)
{
maxY = (int)Math.Floor(y2);
return (int)Math.Ceiling(y1);
}
maxY = (int)Math.Floor(y1);
return (int)Math.Ceiling(y2);
}
private Func<int, double> CreateFunc(Point pt1, Point pt2)
{
var y0 = pt1.Y;
if (y0 == pt2.Y)
{
return x => y0;
}
var m = (double)(pt2.Y - y0) / (pt2.X - pt1.X);
return x => m * (x - pt1.X) + y0;
}
回答2:
@SimpleVar answer is well, but it lacks a good check for valid triangles. (This can cause an overflow problem).
So I do my own implementation for Unity3D:
public static IEnumerable<T> PointsInTriangle<T>(T pt1, T pt2, T pt3)
where T : IPoint
{
/*
// https://www.geeksforgeeks.org/check-whether-triangle-valid-not-sides-given/
a + b > c
a + c > b
b + c > a
*/
float a = Vector2.Distance(new Vector2(pt1.x, pt1.y), new Vector2(pt2.x, pt2.y)),
b = Vector2.Distance(new Vector2(pt2.x, pt2.y), new Vector2(pt3.x, pt3.y)),
c = Vector2.Distance(new Vector2(pt3.x, pt3.y), new Vector2(pt1.x, pt1.y));
if (a + b <= c || a + c <= b || b + c <= a)
{
Debug.LogWarning($"The given points must form a triangle. {{{pt1}, {pt2}, {pt3}}}");
yield break;
}
if (TriangleArea(pt1, pt2, pt3) <= 1)
{
Point center = GetTriangleCenter(pt1, pt2, pt3);
yield return (T)Activator.CreateInstance(typeof(T), center.x, center.y);
return;
}
T tmp;
if (pt2.x < pt1.x)
{
tmp = pt1;
pt1 = pt2;
pt2 = tmp;
}
if (pt3.x < pt2.x)
{
tmp = pt2;
pt2 = pt3;
pt3 = tmp;
if (pt2.x < pt1.x)
{
tmp = pt1;
pt1 = pt2;
pt2 = tmp;
}
}
var baseFunc = CreateFunc(pt1, pt3);
var line1Func = pt1.x == pt2.x ? (x => pt2.y) : CreateFunc(pt1, pt2);
for (var x = pt1.x; x < pt2.x; ++x)
{
int maxY;
int minY = GetRange(line1Func(x), baseFunc(x), out maxY);
for (int y = minY; y <= maxY; ++y)
yield return (T)Activator.CreateInstance(typeof(T), x, y);
}
var line2Func = pt2.x == pt3.x ? (x => pt2.y) : CreateFunc(pt2, pt3);
for (var x = pt2.x; x <= pt3.x; ++x)
{
int maxY;
int minY = GetRange(line2Func(x), baseFunc(x), out maxY);
for (int y = minY; y <= maxY; ++y)
yield return (T)Activator.CreateInstance(typeof(T), x, y);
}
}
private static int GetRange(float y1, float y2, out int maxY)
{
if (y1 < y2)
{
maxY = Mathf.FloorToInt(y2);
return Mathf.CeilToInt(y1);
}
maxY = Mathf.FloorToInt(y1);
return Mathf.CeilToInt(y2);
}
private static Func<int, float> CreateFunc<T>(T pt1, T pt2)
where T : IPoint
{
var y0 = pt1.y;
if (y0 == pt2.y)
return x => y0;
float m = (float)(pt2.y - y0) / (pt2.x - pt1.x);
return x => m * (x - pt1.x) + y0;
}
public static float TriangleArea<T>(T p1, T p2, T p3)
where T : IPoint
{
float a, b, c;
if (!CheckIfValidTriangle(p1, p2, p3, out a, out b, out c))
return 0;
return TriangleArea(a, b, c);
}
public static float TriangleArea(float a, float b, float c)
{
// Thanks to: http://james-ramsden.com/area-of-a-triangle-in-3d-c-code/
float s = (a + b + c) / 2.0f;
return Mathf.Sqrt(s * (s - a) * (s - b) * (s - c));
}
public static Point GetTriangleCenter<T>(T p0, T p1, T p2)
where T : IPoint
{
// Thanks to: https://stackoverflow.com/questions/524755/finding-center-of-2d-triangle
return new Point(p0.x + p1.x + p2.x / 3, p0.y + p1.y + p2.y / 3);
}
public static bool CheckIfValidTriangle<T>(T v1, T v2, T v3, out float a, out float b, out float c)
where T : IPoint
{
a = Vector2.Distance(new Vector2(v1.x, v1.y), new Vector2(v2.x, v2.y));
b = Vector2.Distance(new Vector2(v2.x, v2.y), new Vector2(v3.x, v3.y));
c = Vector2.Distance(new Vector2(v3.x, v3.y), new Vector2(v1.x, v1.y));
if (a + b <= c || a + c <= b || b + c <= a)
return false;
return true;
}
IPoint interface could be a good point for own Point implementations (for libs like Clipper, TessDotNet or Poly2Tri). You can change it at any time (two UnityEngine.Vector2 or System.Drawing.Point).
Hope this helps!
EDIT: I solved all bugs here:
Also I answered my own question asking this: https://stackoverflow.com/a/53734816/3286975
回答3:
First of all, get the bounding box of the triangle:
// This is in psuedocode since I don't know c#
bbox[x1] = min(triangles[1][x], triangles[2][x], triangles[3][x])
bbox[x2] = max(triangles[1][x], triangles[2][x], triangles[3][x])
bbox[y1] = min(triangles[1][y], triangles[2][y], triangles[3][y])
bbox[y2] = max(triangles[1][y], triangles[2][y], triangles[3][y])
Now, for any given point (x,y):
if x < bbox[x1] or y < bbox[y1] or x > bbox[x2] or y > bbox[y2]
then it can't possibly be in the triangle
For all the remaining points, you can use a point-in-triangle algorithm like the ones presented here.
If you want all the points that are in the triangle, you can loop through all the points in the bounding box and see which ones are in and which are not.
来源：https://stackoverflow.com/questions/11075505/get-all-points-within-a-triangle