503. 下一个更大元素 II

题目：

解答：

class Solution:
    def nextGreaterElements(self, nums: List[int]) -> List[int]:
        stk = nums[::-1]
        ans = [-1 for _ in range(len(nums))]
        sz = len(nums) - 1
        for ind, num in enumerate(nums[::-1]):
            while stk and stk[-1] <= num:
                stk.pop()
            ans[sz - ind] = -1 if not stk else stk[-1]
            stk.append(num)
        return ans

 

来源：CSDN

作者：sinat_15355869

链接：https://blog.csdn.net/sinat_15355869/article/details/103777135