问题
I'm looking for regex to do the following in Java:
String originalString = "";
String splitString[] = originalString.spilt(regex);
Some test cases:
Original1: foo bar "simple"
Spilt1: { "foo", "bar", "\"simple\"" }
Original2: foo bar "harder \"case"
Spilt2: { "foo", "bar", "\"harder \"case\"" }
Original3: foo bar "harder case\\"
Spilt3: { "foo", "bar", "\"harder case\\"" }
Some snippets I have come across:
# Does not react to escaped quotes
(?=([^\"]*\"[^\"]*\")*[^\"]*$)
# Finds relevant quotes that surround args
(?<!\\)(?:\\{2})*\"
Thanks!
回答1:
String stringToSplit = This is the string to split;
String[] split = stringToSplit.split("character to split at");
In this case, split[0] would result as ' This ', split[1] would be ' is ', split[2] would be ' the ', split[3] ' string ' split[4] ' to ' split[5] ' split '.
At this point you can do
var0 = split[0];
var1 = split[1];
var2 = split[2];
Where var0 would equal "This"
And so on...
Hope this helps.
回答2:
Regex like this will work for simple cases:
("(.+?)(?<![^\\]\\)")|\S+
But I would not suggest to use RegEx for this task, but take a look at CSV parsers instead.
来源：https://stackoverflow.com/questions/37082706/java-regex-split-string-on-spaces-ignore-spaces-in-quotes-and-escaped-quotes