问题
I'm trying to parse a string of format timestamp with timezone obtained from a DB. The String is as follows :
SimpleDateFormat mdyFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss.SSSSSZ");
SimpleDateFormat sdf = new SimpleDateFormat("dd-MM-yyyy");
Date d1 = mdyFormat.parse("2014-04-01 15:19:49.31146+05:30");
String mdx = sdf.format(d1);
System.out.println(mdx);
Problem is, I get an error saying :
Exception in thread "main" java.text.ParseException: Unparseable date: "2014-04-01 15:19:49.31146+05:30"
at java.text.DateFormat.parse(DateFormat.java:357)
at com.karthik.Timestampvalidate.main(Timestampvalidate.java:31)
Does anyone know how to fix this ?
回答1:
You need to use X
instead of Z
:
SimpleDateFormat mdyFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss.SSSSSX");
See the javadoc for more info.
Note: only available in Java 7+.
回答2:
If you get to use the new JSR 310 date/time APIs in Java 8, you can use the XXX
format to parse the timezone. You need three X
s to get the specific colon-separated offset that you're using.
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyy-MM-dd HH:mm:ss.SSSSSXXX");
TemporalAccessor dateTime = formatter.parse("2014-04-01 15:19:49.31146+05:30");
// returns: {OffsetSeconds=19800},ISO resolved to 2014-04-01T15:19:49.311460
来源:https://stackoverflow.com/questions/22783439/parsing-timestamp-with-timezone-in-java