问题
I'm trying to implement the code below in my WPF project in order to generate DataTemplates on the fly for a DataGrid with dynamic columns. I found the code on StackOverflow here
public DataTemplate Create(Type type)
{
return (DataTemplate)XamlReader.Load(
@"<DataTemplate
xmlns=""http://schemas.microsoft.com/client/2007"">
<" + type.Name + @" Text=""{Binding " + ShowColumn + @"}""/>
</DataTemplate>"
);
}
However, on the XamlReader.Load code, I get the error "cannot convert from 'string' to 'System.Xaml.XamlReader'.
I tried to get around this by changing the code to:
return (DataTemplate)XamlReader.Load(XmlReader.Create(
but I get errors about passing invalid characters in the string.
Also, I am unsure how to pass a TextBlock to this code. I imagined I would just create a TextBlock and pass it as the Type argument, but I get the error "cannot convert from 'System.Windows.Controls.TextBlock' to 'System.Type'
Any help appreciated.
回答1:
public DataTemplate Create(Type type)
{
StringReader stringReader = new StringReader(
@"<DataTemplate
xmlns=""http://schemas.microsoft.com/winfx/2006/xaml/presentation"">
<" + type.Name + @" Text=""{Binding " + ShowColumn + @"}""/>
</DataTemplate>");
XmlReader xmlReader = XmlReader.Create(stringReader);
return XamlReader.Load(xmlReader) as DataTemplate;
}
Call it like this
TextBlock textBlock = new TextBlock();
Create(textBlock.GetType());
回答2:
I replicated your code with the workaround for XmlReader and it worked fine without any issues. Please try this:
return (DataTemplate)XamlReader.Load(
XmlReader.Create(
@"<DataTemplate xmlns=""http://schemas.microsoft.com/client/2007""><" + type.Name + @" Text=""{Binding " + ShowColumn + @"}""/>
</DataTemplate>"
));
This should work.
来源:https://stackoverflow.com/questions/7170937/problems-with-xamlreader-generating-datatemplate