问题
I have a huge ammount of photos that need sorting through. I need to know the dimensions of each photo in order to know or it needs re-sizing. As a programmer I'm convinced there must be a quicker way of doing this.
I got quite far. The following code reads the dir and all the sub dirs. But the moment I try to extract the dimensions the loop halts at 8% of all the pictures that need checking. Could it be PHP is not allowed to do more calculations? What is going on!?
This is how far I got:
checkDir('dir2Check');
function checkDir($dir, $level = 0) {
if ($handle = opendir($dir)) {
while (false !== ($entry = readdir($handle))) {
if (!preg_match('/\./i', $entry)) {
echo echoEntry("DIR\\", $entry, $level);
checkDir($dir.'/'.$entry, $level+1);
} else {
if ($entry != "." && $entry != ".." && $entry != ".DS_Store") {
// if I comment the next line. It loops through all the files in the directory
checkFile($entry, $dir.'/'.$entry, $level);
// this line echoes so I can check or it really read all the files in case I comment the proceeding line
//echo echoEntry("FILE", $entry, $level);
}
}
}
$level--;
closedir($handle);
}
}
// Checks the file type and lets me know what is happening
function checkFile($fileName, $fullPath, $level) {
if (preg_match('/\.gif$/i', $fullPath)) {
$info = getImgInfo(imagecreatefromgif($fullPath));
} else if (preg_match('/\.png$/i', $fullPath)) {
$info = getImgInfo(imagecreatefrompng($fullPath));
} else if (preg_match('/\.jpe?g$/i', $fullPath)){
$info = getImgInfo(imagecreatefromjpeg($fullPath));
} else {
echo "XXX____file is not an image [$fileName]<br />";
}
if ($info) {
echo echoEntry("FILE", $fileName, $level, $info);
}
}
// get's the info I need from the image and frees up the cache
function getImgInfo($srcImg) {
$width = imagesx($srcImg);
$height = imagesy($srcImg);
$info = "Dimensions:".$width."X".$height;
imagedestroy($srcImg);
return $info;
}
// this file formats the findings of my dir-reader in a readable way
function echoEntry($type, $entry, $level, $info = false) {
$output = $type;
$i = -1;
while ($i < $level) {
$output .= "____";
$i++;
}
$output .= $entry;
if ($info) {
$output .= "IMG_INFO[".$info."]";
}
return $output."<br />";
}
回答1:
The following does similar to what you do, only it's using php's DirectoryIterator which in my humble opinion is cleaner and more OOP-y
<?php
function walkDir($path = null) {
if(empty($path)) {
$d = new DirectoryIterator(dirname(__FILE__));
} else {
$d = new DirectoryIterator($path);
}
foreach($d as $f) {
if(
$f->isFile() &&
preg_match("/(\.gif|\.png|\.jpe?g)$/", $f->getFilename())
) {
list($w, $h) = getimagesize($f->getPathname());
echo $f->getFilename() . " Dimensions: " . $w . ' ' . $h . "\n";
} elseif($f->isDir() && $f->getFilename() != '.' && $f->getFilename() != '..') {
walkDir($f->getPathname());
}
}
}
walkDir();
回答2:
You can simply use getimagesize()
list($width, $height) = getimagesize($imgFile);
来源:https://stackoverflow.com/questions/9809985/php-get-dimensions-of-images-in-dir