问题
Im quite new to batch programming and i wanted to remove the last characters on my filename.
10_myfile_12345_6789.txt
11_myfile_12345_0987.txt
I want to remove the last 4 digits on my filename how i could do that?
I have tried this
@echo off
setlocal enabledelayedexpansion
set X=3
set FOLDER_PATH=
pushd %FOLDER_PATH%
for %%f in (*) do if %%f neq %~nx0 (
set "filename=%%~nf"
ren "%%f" "!filename!%%~xf"
)
popd
PAUSE
but it removes on first and last characters, i only saw this here too, im still quite confused how this works
回答1:
With your recent clarification - I would do the following.
@echo off
setlocal enabledelayedexpansion
set FOLDER_PATH=C:\Some\Path\
for %%f in (%FOLDER_PATH%*) do if %%f neq %~nx0 (
set "filename=%%~nf"
ren "%%f" "!filename:~0,-4!%%~xf"
)
PAUSE
This will change your examples
10_myfile_12345_6789.txt
11_myfile_12345_0987.txt
Into
10_myfile_12345_.txt
11_myfile_12345_.txt
If you want to remove the trailing _
simply change !filename:~0,-4!
to !filename:~0,-5!
. This is simple string manipulation.
来源:https://stackoverflow.com/questions/27931611/remove-last-characters-from-my-filenames-in-windows