问题
I have the following loop in my view
<% @posts.each do |post| %>
<%= link_to post do %>
Some html
<% end %>
<% end %>
The above code will generate link as localhost:3000/posts/sdfsdf-sdfsdf
But I would like to have the link as localhost:3000/sdfsdf-sdfsdf
Here is my route
resources :posts, except: [:show]
scope '/' do
match ':id', to: 'posts#show', via: :get
end
回答1:
You could do this:
#config/routes.rb
resources :posts, path: "" #-> domain.com/this-path-goes-to-posts-show
--
Also, make sure you put this at the bottom of your routes; as it will override any preceding routes. For example, domain.com/users
will redirect to the posts
path unless the posts
path is defined at the bottom of the routes.rb
file
--
friendly_id
In order to achieve a slug-based routing system (which works), you'll be best suited to using friendly_id. This allows the .find
method to look up slug
as well as id
for extended models:
#app/models/post.rb
Class Post < ActiveRecord::Base
extend FriendlyID
friendly_id :title, use: [:slugged, :finders]
end
This will allow you to use the following in your controller:
#app/controllers/posts_controller.rb
Class PostsController < ApplicationController
def show
@post = Post.find params[:id] #-> this can be either ID or slug
end
end
回答2:
you need to tell routes what the name of the path gonna be.
in routes.rb you can do something like:
get '/:id', constraints: { the_id: /[a-z0-9]{6}\-[a-z0-9]{6}/ }, to: 'posts#show', as: :custom_name
after that when you run 'rake routes' you will see:
Prefix Verb URI Pattern Controller#Action
custom_name GET /:id(.:format) post#show {:id=>/[a-z0-9]{6}\-[a-z0-9]{6}/}
Now that you have the prefix verb, you can use it to generate the link: <%= link_to 'Show', custom_name_path( post.id ) do %> Some html <% end %>
来源:https://stackoverflow.com/questions/24496657/rails-remove-controller-path-from-the-url