问题
From a Microsoft article:
Address Space Layout Randomization (ASLR)
ASLR moves executable images into random locations when a system boots, making it harder for exploit code to operate predictably. For a component to support ASLR, all components that it loads must also support ASLR. For example, if A.exe consumes B.dll and C.dll, all three must support ASLR. By default, Windows Vista and later will randomize system DLLs and EXEs, but DLLs and EXEs created by ISVs must opt in to support ASLR using the /DYNAMICBASE linker option.
I don't quite get it. Take the base system DLLs loaded by every process on WIndows: NtDll.dll and kernel32.dll.
If a have a non-aware executable, will these system DLLs use ASLR? That is, will they load at a different base address after every system reboot on Win 7 for this executable or will they always load at the same base address after system reboot like they do on Win XP?
To make it more clear what I mean: My typical dummy program's startup stack will look like this:
write_cons.exe!wmain() Line 8 C++
write_cons.exe!__tmainCRTStartup() Line 583 + 0x19 bytes C
write_cons.exe!wmainCRTStartup() Line 403 C
> kernel32.dll!_BaseProcessStart@4() + 0x23 bytes
Looking at the asm of BaseProcessStart, I see on my XP box here:
_BaseProcessStart@4:
7C817054 push 0Ch
7C817056 push 7C817080h
7C81705B call __SEH_prolog (7C8024D6h)
7C817060 and dword ptr [ebp-4],0
...
Now what interests me is the following:
On Windows XP, the address will always be 0x7C817054, regardless of how many times I reboot this machine. If I were on Win7 with ASLR, will this address change between reboots if the executable that loads kernel32.dll is not enabled for ASLR?
(Note: For me, atm., there is only one minor use-case this address would be useful for: In Visual Studio, I can only set a "Data Breakpoint" for assembly level functions, that is a breakpoint @ 0x7... - If I want to break in a specific ntdll.dll or kernel32.dll function, in Windows XP I do not have to adjust my breakpoints between reboots. With ASLR kicking in (the scope of this question) I would have to change the Data Breakpoints between reboots.)
回答1:
Technically whether the system dlls get relocated or not, it shouldn't matter, as the linker will bind to symbols, not addresses. These symbols are resolved by the runtime loader into to addresses for the instanced system dlls, thus your binary should be none the wiser. From what i've seen however, windows 7 will reset the base randomization every reboot, including system dlls(note: this is from debuging WOW64 apps on widows server 2008 R2). You can also do a system wide disabling of ASLR via some registery edits, but thats not really relevant...
Update:
the section on ASLR in this article explains what gets relocated and when. it doesn't mention if the base will reset every reboot, but for system dlls, its never going to be guaranteed to load at the same address twice, reboot or no reboot. the important thing is according to article, everything needs to opt-in to ASLR for system dll's to be relocated.
回答2:
Your program will resolve calls into system DLLs wherever they happen to be loaded. But, unless your executable is linked with /DYNAMICBASE, it will not be given a randomized base address. In other words, your exe will always load at the same base address.
If you want your exe to load at a randomized address, then you have to link it with /DYNAMICBASE, and every DLL that it references must also have been linked with /DYANMICBASE. The system DLLs (starting in Vista) are all linked with /DYNAMICBASE.
来源：https://stackoverflow.com/questions/6396234/aslr-and-windows-system-dlls-for-non-aware-executables