问题
What is the simplest way to create AffineTransform
which maps coordinates from one rectangle to another (float/double rectangles are given)?
UPDATE 1
Rectangles can be absolutely different. For example [(0,0)-(1,1)] and [(150,-14)-(-1000,-14.1)]. And transformation should transform uniformly. For example, rectangle corners should be transformed one to one. For example coordinates (0,0) should turn to (150,-14).
UPDATE 2
I need AffineTransform
object, not just calculation. Because I want to apply it to Graphics
object. Also I would like to have in the form of some concatenation of simple transforms.
UPDATE 3
All the following 3 tests are failed:
public class RectangleTransformTest {
private static final double delta = 0.001;
Rectangle2D r1 = new Rectangle2D.Double(-1, 0, 2, 0.01);
Rectangle2D r2 = new Rectangle2D.Double(10, 20, 400, 300);
AffineTransform t;
Point2D src;
Point2D dst1, dst2;
@Test
public void test1() {
t = new AffineTransform();
t.translate(+r2.getMinX()-r1.getMinX(), +r2.getMinY()-r1.getMinY());
t.scale(r2.getWidth()/r1.getWidth(), r2.getHeight()/r1.getHeight());
}
@Test
public void test2() {
t = new AffineTransform();
t.scale(r2.getWidth()/r1.getWidth(), r2.getHeight()/r1.getHeight());
t.translate(+r2.getMinX()-r1.getMinX(), +r2.getMinY()-r1.getMinY());
}
@Test
public void test3() {
t = new AffineTransform();
t.scale((r2.getMaxX()-r2.getMinX())/(r1.getMaxX()-r1.getMinX()), (r2.getMaxY()-r2.getMinY())/(r1.getMaxY()-r1.getMinY()));
t.translate(+r2.getMinX()-r1.getMinX(), +r2.getMinY()-r1.getMinY());
}
@After
public void comparePoints() {
src = new Point2D.Double(r1.getMinX(), r1.getMinY());
dst1 = new Point2D.Double();
t.transform(src, dst1);
dst2 = new Point2D.Double(r2.getMinX(), r2.getMinY());
assertEquals(dst2.getX(), dst1.getX(), delta);
assertEquals(dst2.getY(), dst1.getY(), delta);
src = new Point2D.Double(r1.getMinX(), r1.getMaxY());
dst1 = new Point2D.Double();
t.transform(src, dst1);
dst2 = new Point2D.Double(r2.getMinX(), r2.getMaxY());
assertEquals(dst2.getX(), dst1.getX(), delta);
assertEquals(dst2.getY(), dst1.getY(), delta);
src = new Point2D.Double(r1.getMaxX(), r1.getMinY());
dst1 = new Point2D.Double();
t.transform(src, dst1);
dst2 = new Point2D.Double(r2.getMaxX(), r2.getMinY());
assertEquals(dst2.getX(), dst1.getX(), delta);
assertEquals(dst2.getY(), dst1.getY(), delta);
src = new Point2D.Double(r1.getMaxX(), r1.getMaxY());
dst1 = new Point2D.Double();
t.transform(src, dst1);
dst2 = new Point2D.Double(r2.getMaxX(), r2.getMaxY());
assertEquals(dst2.getX(), dst1.getX(), delta);
assertEquals(dst2.getY(), dst1.getY(), delta);
}
}
回答1:
To transform from [(a,b)-(c,d)] to [(e,f)-(g,h)] you can perform the following computation:
x' = e + (x - a) * (g - e) / (c - a);
y' = f + (y - b) * (h - f) / (d - b);
Here is the corresponding AffineTransform
code, where r1
is being transformed to r2
:
t = new AffineTransform();
t.translate(r2.getMinX(), r2.getMinY());
t.scale(r2.getWidth()/r1.getWidth(), r2.getHeight()/r1.getHeight());
t.translate(-r1.getMinX(), -r1.getMinY());
来源:https://stackoverflow.com/questions/14015456/create-transform-to-map-from-one-rectangle-to-another