问题
We have following linear regression: y ~ b0 + b1 * x1 + b2 * x2. I know that regress function in Matlab does calculate it, but numpy's linalg.lstsq doesn't (https://docs.scipy.org/doc/numpy-dev/user/numpy-for-matlab-users.html).
回答1:
StatsModels' RegressionResults
has a conf_int() method. Here an example using it (minimally modified version of their Ordinary Least Squares example):
import numpy as np, statsmodels.api as sm
nsample = 100
x = np.linspace(0, 10, nsample)
X = np.column_stack((x, x**2))
beta = np.array([1, 0.1, 10])
e = np.random.normal(size=nsample)
X = sm.add_constant(X)
y = np.dot(X, beta) + e
mod = sm.OLS(y, X)
res = mod.fit()
print res.conf_int(0.01) # 99% confidence interval
回答2:
You can use scipy's linear regression, which does calculate the r/p value and standard error : http://docs.scipy.org/doc/scipy-0.14.0/reference/generated/scipy.stats.linregress.html
EDIT : as underlines by Brian, I had the code from scipy documentation:
from scipy import stats
import numpy as np
x = np.random.random(10)
y = np.random.random(10)
slope, intercept, r_value, p_value, std_err = stats.linregress(x,y)
confidence_interval = 2.58*std_err
来源:https://stackoverflow.com/questions/36400419/how-to-calculate-the-99-confidence-interval-for-the-slope-in-a-linear-regressio