Lua - packing IEEE754 single-precision floating-point numbers

问题

I want to make a function in pure Lua that generates a fraction (23 bits), an exponent (8 bits), and a sign (1 bit) from a number, so that the number is approximately equal to math.ldexp(fraction, exponent - 127) * (sign == 1 and -1 or 1), and then packs the generated values into 32 bits.

A certain function in the math library caught my attention:

The frexp function breaks down the floating-point value (v) into a mantissa (m) and an exponent (n), such that the absolute value of m is greater than or equal to 0.5 and less than 1.0, and v = m * 2^n.

Note that math.ldexp is the inverse operation.

However, I can't think of any way to pack non-integer numbers properly. As the the mantissa returned by this function is not an integer, I'm not sure if I can use it.

Is there any efficient way to do something similar to math.frexp() which returns an integer as the mantissa? Or is there perhaps a better way to pack numbers in the IEEE754 single-precision floating-point format in Lua?

Thank you in advance.

Edit

I hereby present the (hopefully) final version of the functions I made:

function PackIEEE754(number)
    if number == 0 then
        return string.char(0x00, 0x00, 0x00, 0x00)
    elseif number ~= number then
        return string.char(0xFF, 0xFF, 0xFF, 0xFF)
    else
        local sign = 0x00
        if number < 0 then
            sign = 0x80
            number = -number
        end
        local mantissa, exponent = math.frexp(number)
        exponent = exponent + 0x7F
        if exponent <= 0 then
            mantissa = math.ldexp(mantissa, exponent - 1)
            exponent = 0
        elseif exponent > 0 then
            if exponent >= 0xFF then
                return string.char(sign + 0x7F, 0x80, 0x00, 0x00)
            elseif exponent == 1 then
                exponent = 0
            else
                mantissa = mantissa * 2 - 1
                exponent = exponent - 1
            end
        end
        mantissa = math.floor(math.ldexp(mantissa, 23) + 0.5)
        return string.char(
                sign + math.floor(exponent / 2),
                (exponent % 2) * 0x80 + math.floor(mantissa / 0x10000),
                math.floor(mantissa / 0x100) % 0x100,
                mantissa % 0x100)
    end
end
function UnpackIEEE754(packed)
    local b1, b2, b3, b4 = string.byte(packed, 1, 4)
    local exponent = (b1 % 0x80) * 0x02 + math.floor(b2 / 0x80)
    local mantissa = math.ldexp(((b2 % 0x80) * 0x100 + b3) * 0x100 + b4, -23)
    if exponent == 0xFF then
        if mantissa > 0 then
            return 0 / 0
        else
            mantissa = math.huge
            exponent = 0x7F
        end
    elseif exponent > 0 then
        mantissa = mantissa + 1
    else
        exponent = exponent + 1
    end
    if b1 >= 0x80 then
        mantissa = -mantissa
    end
    return math.ldexp(mantissa, exponent - 0x7F)
end

I improved the way to utilise the implicit bit and added proper support for special values such as NaN and infinity. I based the formatting on that of the script catwell linked to.

I thank both of you for your great advice.

回答1:

Multiply the significand you get from math.frexp() by 2^24, and subtract 24 from the exponent to compensate. Now the significand is an integer. Note that the significand is 24 bits, not 23 (you need to account for the implicit bit in the IEEE-754 encoding).

回答2:

Have you seen this?

I think it does what you want in a slighty simpler way.

来源：https://stackoverflow.com/questions/14416734/lua-packing-ieee754-single-precision-floating-point-numbers

标签

floating-point

lua

ieee-754

pack