问题
Any ideas how you might use JQuery's deferred methods with a function that detects all changed forms and submits each one as an Ajax post?
I can get the same thing working if I just list a load of form submissions but if I use...
$('form.changed').each(function(){
return $(this).submitWithAjax();
});
A fuller version of the code that I'm trying to get working is here... at JS Fiddle
Thanks in advance!
回答1:
Instead of ".each()", use ".map()":
var deferreds = $('form.changed').map(function(i, elem) {
return $(this).submitWithAjax();
});
$.when.apply(null, deferreds.get()).then(function() { ... });
The "$.when()" thing lets you bundle up a bunch of deferred objects and wait for all of them to succeed (or for any to fail — note the difference there). It normally allows an arbitrary number of arguments, but since we've got an array I used "apply()".
Note that I've only used this stuff lightly, so read the jQuery API docs to double check :-) edit — also upon re-reading your question, I may have misunderstood you.
回答2:
Delegating the change event to the form fields could solve your problem here.
$('form').delegate('input[type=text], input[type=radio], select', 'change',
function(evt){
// your submits here
console.log('changed!')
});
来源:https://stackoverflow.com/questions/6162855/jquery-deferred-with-each