问题
I have a DataGrid
WPF control and I want to get a specific DataGridCell
. I know the row and column indices. How can I do this?
I need the DataGridCell
because I have to have access to its Content. So if I have (for example) a column of DataGridTextColum
, my Content will be a TextBlock
object.
回答1:
You can use code similar to this to select a cell:
var dataGridCellInfo = new DataGridCellInfo(
dataGrid.Items[rowNo], dataGrid.Columns[colNo]);
dataGrid.SelectedCells.Clear();
dataGrid.SelectedCells.Add(dataGridCellInfo);
dataGrid.CurrentCell = dataGridCellInfo;
I can't see a way to update the contents of a specific cell directly, so in order to update the content of a specific cell I would do the following
// gets the data item bound to the row that contains the current cell
// and casts to your data type.
var item = dataGrid.CurrentItem as MyDataItem;
if(item != null){
// update the property on your item associated with column 'n'
item.MyProperty = "new value";
}
// assuming your data item implements INotifyPropertyChanged the cell will be updated.
回答2:
You can simply use this extension method-
public static DataGridRow GetSelectedRow(this DataGrid grid)
{
return (DataGridRow)grid.ItemContainerGenerator.ContainerFromItem(grid.SelectedItem);
}
and you can get a cell of a DataGrid by an existing row and column id:
public static DataGridCell GetCell(this DataGrid grid, DataGridRow row, int column)
{
if (row != null)
{
DataGridCellsPresenter presenter = GetVisualChild<DataGridCellsPresenter>(row);
if (presenter == null)
{
grid.ScrollIntoView(row, grid.Columns[column]);
presenter = GetVisualChild<DataGridCellsPresenter>(row);
}
DataGridCell cell = (DataGridCell)presenter.ItemContainerGenerator.ContainerFromIndex(column);
return cell;
}
return null;
}
grid.ScrollIntoView
is the key to make this work in case DataGrid is virtualized and required cell is not in view currently.
Check this link for details - Get WPF DataGrid row and cell
回答3:
Here is the code I used:
/// <summary>
/// Get the cell of the datagrid.
/// </summary>
/// <param name="dataGrid">The data grid in question</param>
/// <param name="cellInfo">The cell information for a row of that datagrid</param>
/// <param name="cellIndex">The row index of the cell to find. </param>
/// <returns>The cell or null</returns>
private DataGridCell TryToFindGridCell(DataGrid dataGrid, DataGridCellInfo cellInfo, int cellIndex = -1)
{
DataGridRow row;
DataGridCell result = null;
if (dataGrid != null && cellInfo != null)
{
if (cellIndex < 0)
{
row = (DataGridRow)dataGrid.ItemContainerGenerator.ContainerFromItem(cellInfo.Item);
}
else
{
row = (DataGridRow)dataGrid.ItemContainerGenerator.ContainerFromIndex(cellIndex);
}
if (row != null)
{
int columnIndex = dataGrid.Columns.IndexOf(cellInfo.Column);
if (columnIndex > -1)
{
DataGridCellsPresenter presenter = this.FindVisualChild<DataGridCellsPresenter>(row);
if (presenter != null)
{
result = presenter.ItemContainerGenerator.ContainerFromIndex(columnIndex) as DataGridCell;
}
else
{
result = null;
}
}
}
}
return result;
}`
This assumes that the DataGrid has already been loaded (executed its own Loaded handler).
来源:https://stackoverflow.com/questions/9978119/select-datagridcell-from-datagrid