问题
i'm trying to build a shell script to monitor some log files. I'm using a command like this:
tail -f /var/somelog | grep --line-buffered " some test and p l a c e h o l d e r" | cut -f 3,4,14 -d " "
the log file is like:
some test and p l a c e h o l d e r 3
some test and p l a c e h o l d e r 4
some test and p l a c e h o l d e r 5
some test and p l a c e h o l d e r 6
and so on.. My issue is that the output of the command does not display the last line
some test and p l a c e h o l d e r 6
until line
some test and p l a c e h o l d e r 7
is added to the log.
I hope I made clear my issue. Can anyone help me to solve this? Thank you :)
回答1:
the problem is almost certainly related to how grep and cut buffer their output. here's a hack that should get you around the problem, though i'm sure there are prettier ways to do it:
tail -f /var/somelog | while read line; do echo "$line" | grep "some test and p l a c e h o l d e r" | cut -f 3,4,14 -d " "; done
(don't forget the ; done
at the end of the command)
alternatively, because gawk
doesn't buffer it's output, you could use it in place of cut
to avoid the cumbersome while loop:
tail -f log | grep --line-buffered "some test and p l a c e h o l d e r" | gawk '{print $3,$4,$14}'
check out http://www.pixelbeat.org/programming/stdio_buffering/ for more info on buffering problems.
来源:https://stackoverflow.com/questions/14360640/tail-f-into-grep-into-cut-not-working-properly