问题
We are trying to dynamically generate an IN clause for a native sql query to return a JPA entity. Hibernate is our JPA provider. Our code looks something like this.
@NamedQuery(
name="fooQuery",
queryString="select f from Foo f where f.status in (?1)"
)
....
Query q = entityManager.createNamedQuery("fooQuery");
q.setParameter(1, "('NEW','OLD')");
return q.getResultList();
This doesn't work, the in clause does not recognize any of the values passed in via this manner. Does anyone know of a solution to this problem?
回答1:
JPA supports named list parameters, in your case:
@NamedQuery(
name="fooQuery",
queryString="select f from Foo f where f.status in (?1)"
)
Query q = entityManager.createNamedQuery("fooQuery");
List<String> listParameter = new ArrayList<>();
listParameter.add("NEW");
listParameter.add("OLD");
q.setParameter(1, listParameter);
return q.getResultList();
回答2:
I would recommend to not use a composite parameter for your query, but to split it out individually. Don't specify ('NEW','OLD')
; specify separate parameters of 'NEW'
and 'OLD'
. That may help.
This, of course, may cause problems if your parameter lengths are undefined.
来源:https://stackoverflow.com/questions/831990/using-in-clause-in-a-native-sql-query