问题
I was wondering how I could do something like the following with less css:
.btn {
color : black;
}
.btn:hover {
color : white;
}
.btn-foo {
.btn;
&:hover {
.btn:hover;
}
}
Of-course this is just an example, what need to point is if there is any way to extend the pseudo-class in order to avoid re-type the properties of :hover
pseudo class everywhere I need them. I know I could create a mixin for that but I'm wondering if I could avoid it.
Thanks
回答1:
UPDATE: If you can't modify external files just redefine the selectors, and add missing states:
.btn {
// not adding anything here, won't affect existing style
&:hover {
// adding my own hover state for .btn
background: yellow;
...
}
}
// this will make your foo button appear as in external style
// and have the :hover state just as you defined it above
.btn-foo {
.btn;
}
Better now? :)
You don't need pseudo class. It will just work :)
Try this:
.btn {
background: yellow;
&:hover { // define hover state here
background: green;
}
}
button {
.btn;
}
Each <button class='btn'>
element you create will inherit whatever was defined, including hover state. I think it's one of the main amazing features of LESS.
Hope this helps.
回答2:
In Less 1.4.0(1.4.1?)
This:
.btn {
color : black;
}
.btn:hover {
color : white;
}
.btn-foo:extend(.btn all) {
}
Expands to this:
.btn,
.btn-foo {
color: black;
}
.btn:hover,
.btn-foo:hover {
color: white;
}
Be cautious though, this:
.btn {
color : black;
}
.btn:hover {
color : white;
}
.abc .btn {
margin: 2px;
}
.btn-foo:extend(.btn all) {
}
Will output this:
.btn {
color : black;
}
.btn:hover {
color : white;
}
.abc .btn {
margin: 2px;
}
.btn-foo:extend(.btn all) {
}
I have not looked into SASS more than half an hour, but I believe the later case is its default (or only) @extend behavior.
来源:https://stackoverflow.com/questions/9152989/css-less-class-extend-class-with-pseudo-class