问题
byte[] bytes = new byte[1024];
Assume bytes
is an array filled with audio raw data.
How can I play this byte array using a WaveOut
object?
_waveOut.Init(bytes); // <- Error: cannot resolve method.
_waveOut.Play();
回答1:
I figured it out, here is the solution:
byte[] bytes = new byte[1024];
IWaveProvider provider = new RawSourceWaveStream(
new MemoryStream(bytes), new WaveFormat());
_waveOut.Init(provider);
_waveOut.Play();
回答2:
The accepted answer assumes the byte stream is 44,1kHz, 16 bit, stereo. If you have something else you have to provide the coding in the WaveFormat
byte[] bytes = new byte[1024];
IWaveProvider provider = new RawSourceWaveStream(
new MemoryStream(bytes), new WaveFormat(48000, 16, 1));
_waveOut.Init(provider);
_waveOut.Play();
If your raw data is in fact a wav file you already have the encoding in the header and can use this method
byte[] bytes = new byte[1024];
WaveFileReader reader = new WaveFileReader(new MemoryStream(bytes));
_waveOut.Init(reader);
_waveOut.Play();
来源:https://stackoverflow.com/questions/28792548/how-can-i-play-byte-array-of-audio-raw-data-using-naudio