What's the point of “boost::mpl::identity<T>::type” here?

旧街凉风 提交于 2019-12-28 20:42:52

问题


I was checking the implementation of clamp in boost:

  template<typename T, typename Pred> 
  T const & clamp ( T const& val, 
    typename boost::mpl::identity<T>::type const & lo, 
    typename boost::mpl::identity<T>::type const & hi, Pred p )
  {
//    assert ( !p ( hi, lo ));    // Can't assert p ( lo, hi ) b/c they might be equal
    return p ( val, lo ) ? lo : p ( hi, val ) ? hi : val;
  } 

If I look up the documentation, identity returns the template argument unchanged.

The identity metafunction. Returns X unchanged.

So what's the point of using it here?

Isn't typename boost::mpl::identity<T>::type equivalent to T?


回答1:


A nested-name-specifier creates a non-deduced context. Therefore, a compiler will not attempt to deduce type T based on the second and third parameters declared as:

typename boost::mpl::identity<T>::type const &

Type T will be deduced only based on the type of the first argument, and then used to instantiate the types of the rest parameters. Using the identity type is a common trick to prevent template argument type deduction on certain parameters, that otherwise would result in an ambiguous call error in case the types of arguments differ, but utilize the same type template parameter. It can be also sometimes desired not to let a compiler automatically infer the type, and force a caller do it on his/her own.



来源:https://stackoverflow.com/questions/26885239/whats-the-point-of-boostmplidentityttype-here

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