问题
I am trying to convert an array of bytes into a ZIP file. I got bytes using the following code:
byte[] originalContentBytes= new Verification().readBytesFromAFile(new File("E://file.zip"));
private byte[] readBytesFromAFile(File file) {
int start = 0;
int length = 1024;
int offset = -1;
byte[] buffer = new byte[length];
try {
//convert the file content into a byte array
FileInputStream fileInuptStream = new FileInputStream(file);
BufferedInputStream bufferedInputStream = new BufferedInputStream(
fileInuptStream);
ByteArrayOutputStream byteArrayOutputStream = new ByteArrayOutputStream();
while ((offset = bufferedInputStream.read(buffer, start, length)) != -1) {
byteArrayOutputStream.write(buffer, start, offset);
}
bufferedInputStream.close();
byteArrayOutputStream.flush();
buffer = byteArrayOutputStream.toByteArray();
byteArrayOutputStream.close();
} catch (FileNotFoundException fileNotFoundException) {
fileNotFoundException.printStackTrace();
} catch (IOException ioException) {
ioException.printStackTrace();
}
return buffer;
}
But my problem now is with converting the byte array back into a ZIP file - how can it be done?
Note : The specified ZIP contains two files.
回答1:
To get the contents from the bytes you can use
ZipInputStream zipStream = new ZipInputStream(new ByteArrayInputStream(bytes));
ZipEntry entry = null;
while ((entry = zipStream.getNextEntry()) != null) {
String entryName = entry.getName();
FileOutputStream out = new FileOutputStream(entryName);
byte[] byteBuff = new byte[4096];
int bytesRead = 0;
while ((bytesRead = zipStream.read(byteBuff)) != -1)
{
out.write(byteBuff, 0, bytesRead);
}
out.close();
zipStream.closeEntry();
}
zipStream.close();
回答2:
You probably are looking for code like this:
ZipInputStream z = new ZipInputStream(new ByteArrayInputStream(buffer))
now you can get the zip file contents via getNextEntry()
来源:https://stackoverflow.com/questions/8367126/how-can-i-convert-byte-array-to-zip-file