how to update symfony2/doctrine entity from a @Groups inclusion policy JMSSerializer deserialized entity

跟風遠走 提交于 2019-12-28 12:31:29

问题


I'm trying to update symfony2/doctrine entities using JMSSerializer with an @ExclusionPolicy:None @Groups Inclusion Policy.

 * @Serializer\ExclusionPolicy("none")
 */
 class Foo
 {
    /**
     * @Serializer\Groups({"flag","edit"})
     */
    protected $id;

    /**
     * @Serializer\Groups({"edit"})
     */
    protected $name;

    /**
     * @Serializer\Groups({"flag"})
     */
    protected $flag;

    /**
     * @Serializer\Exclude()
     */
    protected $createdBy;
 }

reference: http://jmsyst.com/libs/serializer/master/reference/annotations

the result for the following record:

Foo (id:1, name:'bar', flagged:false ,created_by:123)

is serialized using Group inclusion to avoid serializing information I don't need (associations, blobs, etc..) so when I want to update an entity I deserialize only the updated fields of the entity from the JSON.

$foo->setFlagged(true);
$data = $serializer->serialize($foo, 'json', SerializationContext::create()->setGroups(array("flag")));

result:
{id:1,flagged:true}

which when passed back to the application deserializes into the entity

$foo = $serializer->deserialize($jsonFoo,'Foo','json');

result:
Foo (id:1, name:null, flagged:true, created_by:null)

The problem is when I try to merge the entity back into the doctrine entity manager:

$foo = $em->merge($foo);
$em->persist($foo);
$em->flush();

The resulting foo is trying to update excluded properties (name,created_by) with null.

How do I tell JMSSerializer or Doctrine Entity Managers merge that I don't want to overwrite existing properties with null?


回答1:


I found the answer.

$serializer is a service created by the symfony2 integration bundle JMSSerializerBundle.

The default service is jms_serializer.serializer initializes the JMSSerializer with the default Object Constructor UnserializeObjectConstructor and for doctrine I needed to deserialize with the DoctrineObjectConstructor.

because I only use JMSSerializer in the project for serialize/deserialize of doctrine entities, I overwrote JMSSerializerBundle's jms_serializer.object_constructor with the alias of the proper object constructor service.

<service id="jms_serializer.object_constructor" alias="jms_serializer.doctrine_object_constructor" public="false"/>

Is there a better way to configure what object constructor the serializer uses?

I also added the proper context to deserialize:

$serializer->deserialize($jsonFoo,'Foo','json', DeserializationContext::create()->setGroups(array('flag')));

result:
Foo (id:1, name:'bar', flagged:true ,created_by:123)

Using the doctrine object constructor, it figures out that I want to find the object and only apply updates to fields provided in $jsonFoo (and the flag group). This totally eliminates the need for doctrines entity manager merge and I can just persist the object properly.

$em->persist($foo);
$em->flush();



回答2:


in addition to @Heyflynn's answer (thanks!), I needed this to work with doctrine_mongodb, so I modified my services.yml as follows:

services:
    jms_serializer.doctrine_object_constructor:
        class:        %jms_serializer.doctrine_object_constructor.class%
        public:       false
        arguments:    ["@doctrine_mongodb", "@jms_serializer.unserialize_object_constructor"]

    jms_serializer.object_constructor:
        alias: jms_serializer.doctrine_object_constructor

important fact is the @doctrine_mongodb as argument for jms_serializer.doctrine_object_constructor instead the original doctrine parameter in the bundle's services.xml:

    <service id="jms_serializer.doctrine_object_constructor" class="%jms_serializer.doctrine_object_constructor.class%" public="false">
        <argument type="service" id="doctrine"/>
        <argument type="service" id="jms_serializer.unserialize_object_constructor"/>
    </service>
    <service id="jms_serializer.unserialize_object_constructor" class="%jms_serializer.unserialize_object_constructor.class%" public="false" />
    <service id="jms_serializer.object_constructor" alias="jms_serializer.unserialize_object_constructor" public="false" />



回答3:


To use JMS deserializer for MongoDB documents and ORM entities you can use

jms_serializer.doctrine_mongodb_object_constructor:
    class:        %jms_serializer.doctrine_object_constructor.class%
    public:       false
    arguments:    ["@doctrine_mongodb", "@jms_serializer.unserialize_object_constructor"]

jms_serializer.doctrine_object_constructor:
    class:        %jms_serializer.doctrine_object_constructor.class%
    public:       false
    arguments:    ["@doctrine", "@jms_serializer.doctrine_mongodb_object_constructor"]

jms_serializer.object_constructor:
    alias: jms_serializer.doctrine_object_constructor
    public: false

As you see in jms_serializer.doctrine_object_constructor second argument (fallbackConstructor) is jms_serializer.doctrine_mongodb_object_constructor it means that if your object isn't entity then jms will try to use fallbackConstructor and if your deserialised object isn't Document either then will be used default unserialize_object_constructor

if you deserialize entity

$em->persist($foo);
$em->flush();

if document

$dm->persist($foo);
$dm->flush();


来源:https://stackoverflow.com/questions/16525849/how-to-update-symfony2-doctrine-entity-from-a-groups-inclusion-policy-jmsserial

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