问题
Is there a standard value for (or method for obtaining) epsilon in Python? I need to compare floating point values and want to compare against the smallest possible difference.
In C++ there's a function provided numeric_limits::epsilon( ) which gives the epsilon value for any given data type. Is there an equivalent in Python?
回答1:
The information is available in sys.float_info, which corresponds to float.h in C99.
>>> import sys
>>> sys.float_info.epsilon
2.220446049250313e-16
回答2:
As strcat posted, there is sys.float_info.epsilon.
But don't forget the pitfalls of using it as an absolute error margin for floating point comparisons. E.g. for large numbers, rounding error could exceed epsilon.
If you think you need a refresher, the standard reference is David Goldberg's What Every Computer Scientist Should Know About Floating-Point Arithmetic, or for a simpler review you can check out The Floating Point Guide.
回答3:
Surprised nobody mentioned this here; I think many people would use numpy.finfo( type(variable) ).eps instead. Or .resolution if it is to assess precision.
Note that finfo is only for floating point types, and that it also works with Python's own float type (i.e. not restricted to numpy's types). The equivalent for integer types is iinfo, though it does not contain precision information (because, well, why would it?).
回答4:
If you cannot find a function to do that, remember that the algorithm to calculate the machine precision is very easy (you can test with your favourite programming language).E.g, for python:
eps = 1.0
while eps + 1 > 1:
eps /= 2
eps *= 2
print("The machine precision is:", eps)
In my case, I got:
The machine precision is: 2.220446049250313e-16
来源：https://stackoverflow.com/questions/9528421/value-for-epsilon-in-python