How to make a Jenkins/Hudson job surveil some others jobs and decide whether to build or not?

问题

PROBLEM

Given that all the jobs have string LEVEL_X in it's job name, where X is a number > 1. I want every job with X = n to surveil every job with X = n-1, and start building if each of them is finished with success. And I want the job with X = n to surveil the other jobs with an interval of 1 minute.

First of all, I am interested in knowing what the best way is to do that, second I want the solution if one can be implemented by a small script, maybe a groovy script which can be run in system groovy script using the GROOVY PLUGIN.

回答1:

Here are some hints and code snippets:

• There is a Groovy Script console at http://<jenkins-server>/script that will help you with debugging your scripts.
• Here is a link to Jenkins Java API.

• Code snippet that outputs all job names:

  def hi = hudson.model.Hudson.instance
     hi.getItems(hudson.model.Project).each {project ->
     println(project.displayName)
  }
  

• Code snippet that extracts n from LEVEL_n (implemented as closure):

  def level = { name ->
    def ret = 0
    name.eachMatch(~'LEVEL_([1-9]+[0-9*])', {ret = it[1].toInteger()})
    return ret
  }
  

• Code snippet that gets statuses for all the latest builds:

  def hi = hudson.model.Hudson.instance
  hi.getItems(hudson.model.Project).each {project ->
    println(project.lastBuild.result)
  }
  

• Link to the method that starts a build.

Note: things get a bit hairier if you are using Matrix builds. But as long as you don't this should be enough.

来源：https://stackoverflow.com/questions/10777663/how-to-make-a-jenkins-hudson-job-surveil-some-others-jobs-and-decide-whether-to