If mouse over for over 2 seconds then show else don't?

独自空忆成欢 提交于 2019-12-28 03:35:07

问题


Here is a jQuery slide function I have applied to a div on hover in order to slide a button down.

It works fine except that now everytime someone moves in and out of it, it keeps bobbing up and down.

I figured if I put a one or two second delay timer on it it would make more sense.

How would I modify the function to run the slide down only if the user is on the div for over a second or two?

<script type="text/javascript" src="http://code.jquery.com/jquery-latest.min.js "></script>
<script type="text/javascript">

$("#NewsStrip").hover(
function () {
    $("#SeeAllEvents").slideDown('slow');    },
function () {
    $("#SeeAllEvents").slideUp('slow');
});

</script>

回答1:


You need to set a timer on mouseover and clear it either when the slide is activated or on mouseout, whichever occurs first:

var timeoutId;
$("#NewsStrip").hover(function() {
    if (!timeoutId) {
        timeoutId = window.setTimeout(function() {
            timeoutId = null; // EDIT: added this line
            $("#SeeAllEvents").slideDown('slow');
       }, 2000);
    }
},
function () {
    if (timeoutId) {
        window.clearTimeout(timeoutId);
        timeoutId = null;
    }
    else {
       $("#SeeAllEvents").slideUp('slow');
    }
});

See it in action.




回答2:


var time_id;

$("#NewsStrip").hover(
function () {
    if (time_id) {
        clearTimeout(time_id);
    } 
    time_id = setTimeout(function () {
        $("#SeeAllEvents").stop(true, true).slideDown('slow');
    }, 2000);
}, function () {
    if (time_id) {
        clearTimeout(time_id);
    } 
    time_id = setTimeout(function () {
        $("#SeeAllEvents").stop(true, true).slideUp('slow');
    }, 2000);
});


来源:https://stackoverflow.com/questions/11263636/if-mouse-over-for-over-2-seconds-then-show-else-dont

易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!