Print second last column/field in awk

问题

I want to print the second last column or field in awk. The number of fields is variable. I know that I should be able to use $NF but not sure how it can be used.

And this does not seem to work:

awk ' { print ( $NF-- )  } '

回答1:

awk '{print $(NF-1)}'

Should work

回答2:

Small addition to Chris Kannon' accepted answer: only print if there actually is a second last column.

(
echo       | awk 'NF && NF-1 { print ( $(NF-1) ) }'
echo 1     | awk 'NF && NF-1 { print ( $(NF-1) ) }'
echo 1 2   | awk 'NF && NF-1 { print ( $(NF-1) ) }'
echo 1 2 3 | awk 'NF && NF-1 { print ( $(NF-1) ) }'
)

回答3:

It's simplest:

 awk '{print $--NF}'

The reason the original $NF-- didn't work is because the expression is evaluated before the decrement, whereas my prefix decrement is performed before evaluation.

回答4:

awk ' { print ( $(NF-1) ) }' file

回答5:

You weren't far from the result! This does it:

awk '{NF--; print $NF}' file

This decrements the number of fields in one, so that $NF contains the former penultimate.

Test

Let's generate some numbers and print them on groups of 5:

$ seq 12 | xargs -n5
1 2 3 4 5
6 7 8 9 10
11 12

Let's print the penultimate on each line:

$ seq 12 | xargs -n5 | awk '{NF--; print $NF}'
4
9
11

回答6:

Perl solution similar to Chris Kannon's awk solution:

perl -lane 'print $F[$#F-1]' file

These command-line options are used:

n loop around every line of the input file, do not automatically print every line
l removes newlines before processing, and adds them back in afterwards
a autosplit mode – split input lines into the @F array. Defaults to splitting on whitespace
e execute the perl code

The @F autosplit array starts at index [0] while awk fields start with $1.
$#F is the number of elements in @F

回答7:

Did you tried to start from right to left by using the rev command ? In this case you just need to print the 2nd column:

seq 12 | xargs -n5 | rev | awk '{ print $2}' | rev
4
9
11

回答8:

First decrements the value and then print it -

awk ' { print $(--NF)}' file

rev file|cut -d ' ' -f2|rev

回答9:

If you have many columns and want to print all but not the three cloumns in the last, then this might help

awk '{ $NF="";$(NF-1)="";$(NF-2)="" ; print $0 }'

来源：https://stackoverflow.com/questions/2096490/print-second-last-column-field-in-awk

标签

awk

gawk