Difference in System. exit(0) , System.exit(-1), System.exit(1 ) in Java

问题

I'd like to know the difference between the following in Java

System.exit(0);
System.exit(-1);
System.exit(1);

When do I have to use the above code appropriately?

回答1:

The parameter of exit should qualify if the execution of the program went good or bad. It's a sort of heredity from older programming languages where it's useful to know if something went wrong and what went wrong.

Exit code is

0 when execution went fine;
1, -1, whatever != 0 when some error occurred, you can use different values for different kind of errors.

If I'm correct exit codes used to be just positive numbers (I mean in UNIX) and according to range:

1-127 are user defined codes (so generated by calling exit(n))
128-255 are codes generated by termination due to different unix signals like SIGSEGV or SIGTERM

But I don't think you should care while coding on Java, it's just a bit of information. It's useful if you plan to make your programs interact with standard tools.

回答2:

Zero => Everything Okay

Positive => Something I expected could potentially go wrong went wrong (bad command-line, can't find file, could not connect to server)

Negative => Something I didn't expect at all went wrong (system error - unanticipated exception - externally forced termination e.g. kill -9)

(values greater than 128 are actually negative, if you regard them as 8-bit signed binary, or twos complement)

There's a load of good standard exit-codes here

回答3:

System.exit(system call) terminates the currently running Java virtual machine by initiating its shutdown sequence. The argument serves as a status code.

By convention, a nonzero status code indicates abnormal termination.

  System.exit(0) or EXIT_SUCCESS;  ---> Success
  System.exit(1) or EXIT_FAILURE;  ---> Exception
  System.exit(-1) or EXIT_ERROR;   ---> Error

回答4:

A non-zero exit status code, usually indicates abnormal termination. if n != 0, its up to the programmer to apply a meaning to the various n's.

From https://docs.oracle.com/javase/7/docs/api/java/lang/System.html.

回答5:

Here is the answer.

System.exit(0);// normal termination - Successful - zero
System.exit(-1);//Exit with some Error
System.exit(1);//one or any positive integer // exit with some Information message

回答6:

exit(0) generally used to indicate successful termination. exit(1) or exit(-1) or any other non-zero value indicates unsuccessful termination in general.

回答7:

A good gotcha is any error code > 255 will be converted to error code % 256. One should be specifically careful about this if they are using a custom error code > 255 and expecting the exact error code in the application logic. http://www.tldp.org/LDP/abs/html/exitcodes.html

回答8:

the difference of the numbers put in system.exit() is explained in other answers. but the REAL DIFFERENCE is that System.exit() is a code that gets returned to the invoking process. If the program is being invoked by the Operating system then the return code will tell the OS that if system.exit() returned 0 than everything was ok but if not something went wrong, then there could be some handlers for that in the parent process

回答9:

As others answer 0 meaning success, otherwise.

If you using bat file (window) System.exit(x) will effect.

Code java (myapp):

if (error < 2){
    help();
    System.exit(-1);    
}
else{
    doSomthing();
    System.exit(0);
}

}

bat file:

java -jar myapp.jar
if %errorlevel% neq 0 exit /b %errorlevel%
rem -- next command if myapp is success --

回答10:

System.exit(0) by convention, a nonzero status code indicates abnormal termination.

System.exit(1) -It means termination unsuccessful due to some error

回答11:

class calc{
public static void main(String args[])
{
    int a, b, c;
    char ch;
    do{

        Scanner s=new Scanner(System.in);

                System.out.print("1. Addition\n");
                System.out.print("2. Substraction\n");
                System.out.print("3. Multiplication\n");
                System.out.print("4. Division\n");
                System.out.print("5. Exit\n\n");

                System.out.print("Enter your choice : ");
                ch=s.next().charAt(0);
                    switch (ch)
                    {
                        case '1' :
                        Addition chose1=new Addition();
                        chose1.add();
                        break;

                        case '2' :
                        Substraction chose2=new Substraction();
                        chose2.sub();
                        break;

                        case '3' :
                        Multiplication chose3= new Multiplication();
                        chose3.multi();
                        break;

                        case '4' :
                        Division chose4=new Division();
                        chose4.divi();
                        break;

                        case '5' :
                        System.exit(0);
                        break;

                        default :
                        System.out.print("wrong choice!!!");
                        break;
                    }
        System.out.print("\n--------------------------\n");                     
    }while(ch !=5); 
}

}

In the above code when its System.exit(0); and when i press case 5 it exits properly but when i use System.exit(1); and press case 5 it exits with error and again when i try with case 15 it exits properly by this i got to know that, when ever we put any int inside argument it specifies that, it take the character from that position i.e if i put (4) that it means take 5th character from that string if its (3) then it means take 4th character from that inputed string

来源：https://stackoverflow.com/questions/2434592/difference-in-system-exit0-system-exit-1-system-exit1-in-java

标签

java

system.exit