问题
I have written following code but it is throwing array index out of range exception
String options = "" + args[0];
if (options.toLowerCase().contains("failover"))
{
dataToPass[0]= "failover";
callScript("Clus1toNfastfastsamehost",dataToPass);
}
Exceptions: exception_name = java.lang.ArrayIndexOutOfBoundsException exception_message = Array index out of range: 1
回答1:
Well, Either you are not allocated enough memory the dataToPass[] or you have not pass arguments to the program. If no arguments is passed then args, it's a zero length array. Debugging will be a good option for you mate.
回答2:
You are not passing an argument to your program.
回答3:
Well, it's a straightforward exception. Check all your array lengths. How many items are in args? In dataToPass? Consider using a debugger.
回答4:
UPDATE WITH CODE FIX
String options = ""
if (args.length > 0)
options += args[0]
Original comments:
There are two places you reference an array in the example code. args[0]
and dataToPass[0]
It must be one of those two. So, a) you are not passing any arguments to the programs and args[0] is not defined -- this seems strange to me because I thought args[0]
was the program name or b) dataToPass[0]
was not allocated -- is dataToPass a zero length array and not a 1 length array?
来源:https://stackoverflow.com/questions/2011247/string-conversion-in-java-is-throwing-array-index-out-of-range-exception