java.lang.Runtime exception “Cannot run program”

问题

I am getting an exception like java.io.IOException: Cannot run program cat /home/talha/* | grep -c TEXT_TO_SEARCH": error=2, No such file or directory while executing the command below despite that there are no issues when I execute the same command through the terminal. I need to execute and return the output of the command below:

cat /home/talha/* | grep -c TEXT_TO_SEARCH

Here is the method used to execute commands using Runtime class:

public static String executeCommand(String command) {

    StringBuffer output = new StringBuffer();

    Process p;
    try {
        p = Runtime.getRuntime().exec(command);
        p.waitFor();
        BufferedReader reader = new BufferedReader(new InputStreamReader(p.getInputStream()));

        String line = "";
        while ((line = reader.readLine()) != null) {
            output.append(line + "\n");
        }

    } catch (Exception e) {
        e.printStackTrace();
    }

    return output.toString();
}

回答1:

Runtime.exec does not use a shell (like, say, /bin/bash); it passes the command directly to the operating system. This means wildcards like * and pipes (|) will not be understood, since cat (like all Unix commands) does not do any parsing of those characters. You need to use something like

p = new ProcessBuilder("bash", "-c", command).start();

or, if for some bizarre reason you need to stick to using the obsolete Runtime.exec methods:

p = Runtime.getRuntime().exec(new String[] { "bash", "-c", command });

If you are only running that cat/grep command, you should consider abandoning the use of an external process, since Java code can easily traverse a directory, read lines from each file, and match them against a regular expression:

Pattern pattern = Pattern.compile("TEXT_TO_SEARCH");
Charset charset = Charset.defaultCharset();

long count = 0;

try (DirectoryStream<Path> dir =
    Files.newDirectoryStream(Paths.get("/home/talha"))) {

    for (Path file : dir) {
        count += Files.lines(file, charset).filter(pattern.asPredicate()).count();
    }
}

Update: To recursively read all files in a tree, use Files.walk:

try (Stream<Path> tree =
    Files.walk(Paths.get("/home/talha")).filter(Files::isReadable)) {

    Iterator<Path> i = tree.iterator();
    while (i.hasNext()) {
        Path file = i.next();
        try (Stream<String> lines = Files.lines(file, charset)) {
            count += lines.filter(pattern.asPredicate()).count();
        }
    };
}

回答2:

$PATH is an environment variable that tells the system where to search for executable programs (it's a list of directories separated by colons). It is usually set in your .bashrc or .cshrc file but this is only loaded when you log in. When Java runs, $PATH is likely not set because the rc file is not executed automatically, so the system can't find programs without specifying exactly where they are. Try using /bin/cat or /usr/bin/cat instead of just cat and see if it works. If it does, $PATH is your problem. You can add $PATH=/bin:/usr/bin to your script or just leave it with the directory name specified (e.g. /bin/cat).

Just because you can execute it in a login session doesn't mean it will work the same when a daemon like your Java program runs. You have to know what's in your .bashrc or .cshrc file and even sometimes how the system file is written (/etc/bashrc) in order to know how to write a script that runs under a daemon. Another consideration is that daemons often run under the context of a different user, and that throws things off, too.

来源：https://stackoverflow.com/questions/44500899/java-lang-runtime-exception-cannot-run-program

标签

java

Linux

unix

cat

runtime.exec