问题
Here is the problem I am trying to send an image to a remote server using the class MultipartPostData.
I build my PostData with the following code :
PostData body = new MultipartPostData(MultipartPostData.DEFAULT_CHARSET, false);
body.append("deviceID", ""+DeviceInfo.getDeviceId());
body.append("synchro", "true");
body.append("shoot_lat", ""+latitude);
body.append("shoot_long", ""+longitude);
body.append("shoot_place", ""+city);
body.append("shoot_time", String.valueOf(time));
body.append("ref_data", "filename=\"photo.jpg\"");
//image is a byte[]
body.setData(image);
I think something is wrong in the way of setting the image because the server can not get this body (if I print the data received and analysed by the server in the body of the request, I get a blank string).
Can anybody help to build a working request to send an image ?
Thanks a lot.
回答1:
Ok, I finally found the answer by myself.
private static final String BOUNDARY = "---------------------------14737809831466499882746641449";
public void createHttpMultipartRequest(String url, Hashtable params, String fileField, String fileName, String fileType, byte[] fileBytes) throws Exception
{
this.url = url;
String boundary = getBoundaryString();
String boundaryMessage = getBoundaryMessage(boundary, params, fileField, fileName, fileType);
String endBoundary = "\r\n--" + boundary + "--\r\n";
ByteArrayOutputStream bos = new ByteArrayOutputStream();
bos.write(boundaryMessage.getBytes());
if(fileField != null)
{
bos.write(fileBytes);
}
bos.write(endBoundary.getBytes());
this.postBytes = bos.toByteArray();
bos.close();
}
String getBoundaryString()
{
return BOUNDARY;
}
String getBoundaryMessage(String boundary, Hashtable params, String fileField, String fileName, String fileType)
{
StringBuffer res = new StringBuffer("--").append(boundary).append("\r\n");
String intermediateBoundary = "\r\n--" + boundary + "\r\n";
Enumeration keys = params.keys();
while(keys.hasMoreElements())
{
String key = (String)keys.nextElement();
String value = (String)params.get(key);
res.append("Content-Disposition: form-data; name=\"").append(key).append("\"\r\n")
.append("\r\n").append(value);
if(keys.hasMoreElements())
{
res.append(intermediateBoundary);
}
}
if(fileField != null)
{
res.append(intermediateBoundary);
res.append("Content-Disposition: form-data; name=\"").append(fileField).append("\"; filename=\"").append(fileName).append("\"\r\n")
.append("Content-Type: ").append(fileType).append("\r\n\r\n");
}
return res.toString();
}
The Hashtable contains all the parameters of the form. And the fileBytes contains the data to send.
来源:https://stackoverflow.com/questions/5342577/blackberry-jde-how-to-upload-an-image-in-server-using-multipartpostdata