问题
I have two string 1 represent date and 2nd time. have to convert same into date format in Mule-dataweave
input :- s1= 20161228(yyyymmdd), s2= 1608(hhmm)
output :- 12-28-2016 16:08:00(mm-dd-yyyy hh:mm:ss) in date format.
Any Help?
回答1:
This should work
%dw 1.0
%output application/java
%var s1= 20161228 // (yyyymmdd),
%var s2= 1608 //(hhmm)
---
output : (s1 ++ s2) as :localdatetime {format:"yyyyMMddHHmm"} as :string {format:"MM-dd-yyyy HH:mm:ss"}
Hope this helps.
回答2:
{ "data":payload.date as {format:"MM/DD/YY"}as :string{format:"dd/mm/yy"} }
回答3:
You can convert as given below.
DATUM: input as :localdatetime {format: "yyyymmdd"} as :string {format: "yyyyMMdd"},
DATUM: now as :string {format: "mm-dd-yyyy"}
For more about date formats see the below link.
https://docs.mulesoft.com/mule-user-guide/v/3.8/dataweave-types#dates
来源:https://stackoverflow.com/questions/40299183/how-to-convert-yyyymmdd-into-mm-dd-yyyy-in-dataweave