问题
I am having problems of conversion through string->byte->byte[]
What I have done so far:
double db = 1.00;
double ab = db*100;
int k = (int) ab;
String aa = String.format("%06d", k);
String first = aa.substring(0,2);``
String second = aa.substring(2,4);
String third = aa.substring(4,6);
String ff = "0x"+first;
String nn = "0x"+second;
String yy = "0x"+third;
I want to write those bytes to an byte[]. What I mean is:
byte[] bytes = new byte[]{(byte) 0x02, (byte) 0x68, (byte) 0x14,
(byte) 0x93, (byte) 0x01, ff,nn,yy};
in this order and casted with 0x's. Any help is greatly appriciated.
Regards, Ali
回答1:
You can use Byte.decode()
Decodes a String into a Byte. Accepts decimal, hexadecimal, and octal numbers given by the following grammar:
DecodableString:
Signopt DecimalNumeral
Signopt 0x HexDigits
Signopt 0X HexDigits
Signopt # HexDigits
Signopt 0 OctalDigits
Below code will print 10
, 11
which is value of 0XA
, 0XB
byte[] temp = new byte[2];
temp[0] = Byte.decode("0xA");
temp[1] = Byte.decode("0xB");
System.out.println(temp[0]);
System.out.println(temp[1]);
回答2:
As I see, the main question here is how to convert a 2 char String representing a hexa number to a byte type. The Byte class has a static method parseByte(String s, int radix) that can parse a String to number using the radix you want (in this case, 16). Here is an example of how you can do the parsing and save the result in a byte array:
public static void main(String [] args){
System.out.println(Arrays.toString(getBytes("0001020F")));
}
public static byte[] getBytes(String str) {
byte [] result = new byte[str.length() / 2]; //assuming str has even number of chars...
for(int i = 0; i < result.length; i++){
int startIndex = i * 2;
result[i] = Byte.parseByte(str.substring(startIndex, startIndex + 2), 16);
}
return result;
}
来源:https://stackoverflow.com/questions/12385073/string-to-byte-then-byte-0xformat