问题
I'm programming a stepper motor with PIC16F84 in MPlab IDE. My program returns it's starting point after I call it's delay method. To be more spesific, some of code snippets here.
main method to drive program
int main(int argc, char** argv) {
TRISB = 0; // PORT B as output port
PORTB = 0x0F;
stepForward(25);
activateRelay();
waitForSeconds(3000);
deActivateRelay();
stepBackward(50);
//Since step forward method steps for 100, this will return to initial state
stepForward(25);
return (EXIT_SUCCESS);
}
Step forward method
void stepForward(unsigned int stepCount){
while(0 < stepCount) {
PORTB = 0b00000001;
waitForSeconds(500);
PORTB = 0b00000010;
waitForSeconds(500);
PORTB = 0b00000100;
waitForSeconds(500);
PORTB = 0b00001000;
waitForSeconds(500);
stepCount--;
}
}
And the method for delaying system
void waitForSeconds(unsigned int miliSeconds){
//DelayUs(miliSeconds);
for(;miliSeconds > 0; miliSeconds--)
for(unsigned short x = 333; x > 0 ; x--){
}
}
After the second waitFor
method called from stepForward
method, program returns into TRISB = 0;
part of the main
method.
I'm new at pic programming, so my fault would be very easy one. I'm looking for help. Thanks.
回答1:
If the program counter jumps back to 0 unexpectedly, the PIC is resetting. There are many causes of reset, depending on the PIC. A common one is watchdog timeout, and you don't seem to be kicking the watchdog, so have you disabled it in the config bits? Status register bit 4 will tell you if a watchdog timeout occurred.
来源:https://stackoverflow.com/questions/23085280/program-returns-to-its-main-point-unexpectedly-at-pic-c-in-mplab