问题
I'm using Eric Hynds jQuery MultiSelect Widget. I'm actually using 2 separate widgets that when checked, creates a dynamic checkbox w/ value attached to a corresponding 'Main' checkbox if 'Main' checkbox is checked. Please see my fiddle with comments inside to illustrate my problem:http://jsfiddle.net/3u7Xj/52/
How to separate the 2 widgets to show in corresponding sections and still only allow the user to choose 2 combined from either?
$(document).ready(function() {
$(".multiselect").multiselect({
header: "Choose up to 5 areas total",
click: function (event, ui) {
if (ui.checked && $(".multiselect").children(":checked").length >= 2) {
return false;
}
var lbl = ui.value;
if(ui.checked){
var ctrl = '<input type="checkbox" name="chk" checked="checked" class="chk" id="'+lbl+'">';
$("[id^=Main]:checked").each(function(){
$(this).nextAll('.holder:first').append('<div>'+ctrl+lbl+'</div>');
});
}
else {
$("[id^=Main]:checked").each(function(){
$(this).nextAll('.holder:first').find('div input[id="'+lbl+'"]').parent().remove();
});
}
},
selectedList:5
});
});
回答1:
So I modified the condition and it works as it should, I hope that it will suit you.
var number1=$("#dropdown1").children(":checked").length,
number2=$("#dropdown2").children(":checked").length;
if (ui.checked && ((number1 + number2 >=4) || $(this).children(":checked").length >= 2)){
return false;
}
Demo here
If you want to only two from both selects and modify the condition as follows:
var number1=$("#dropdown1").children(":checked").length,
number2=$("#dropdown2").children(":checked").length;
if (ui.checked && ((number1 + number2 >=2) || $(this).children(":checked").length >= 2)){
return false;
}
Demo here
Adapted to the requirements in the comment
individual segments inserted into the div. Adjusted control function click
to:
$(this).parent("div").find("[id^=Main]:checked").each(function(){
$(this).nextAll('.holder:first').append('<div>'+ctrl+lbl+'</div>');
});
Demo here
来源:https://stackoverflow.com/questions/21335744/jquery-js-separating-2-drop-down-values