问题
I have a file with the following type of data:
4-11-11 12:59:01,C,26,668
4-11-11 12:59:31,C,26,668
4-11-11 13:00:01,C,26,668
4-11-11 13:00:31,C,26,668
4-11-11 13:01:01,C,26,668
4-11-11 13:01:31,C,26,668
and I want the following output:
12:59:01 26.668
12:59:31 26.668
13:00:01 26.668
13:00:31 26.668
13:01:01 26.668
13:01:31 26.668
This works just fine in the termal with the following line, but not in a bash script, it just gives me an empty file. The problem started after I added the awk part.
cut -d ' ' -f2 $file | cut -d ',' -f-1,3- | awk -f tmp.csv -F"," '{print $1 " " $2 "." $3}' | sed 's/"//' > tmp.csv
cp tmp.csv > $file
Could anyone explain why this won't work in a script?
Thanks!
回答1:
With this awk
it can be easier:
$ awk -F'[ ,]' '{print $2, $4"."$5}' file
12:59:01 26.668
12:59:31 26.668
13:00:01 26.668
13:00:31 26.668
13:01:01 26.668
13:01:31 26.668
-F'[ ,]'
sets two possible delimiters: space and comma.print $2, $4"."$5
prints the 2nd, 4th and 5th fields based on those delimiters.
Regarding why your script did not work, it is just because you added -f tmp.csv
unnecessarily.
$ cut -d ' ' -f2 a | cut -d ',' -f-1,3- | awk -F"," '{print $1 " " $2 "." $3}' | sed 's/"//'
12:59:01 26.668
12:59:31 26.668
13:00:01 26.668
13:00:31 26.668
13:01:01 26.668
13:01:31 26.668
Also you use -f tmp.csv
and then > tmp.csv
which does not make sense. Note a file cannot be used as stdin and stdout at the same time.
回答2:
I guess your surroundings in the script are to blame, but the whole thing can be done using just read
:
while IFS=' ,' read a b c d e
do
echo "$b $d.$e"
done < inputfile
Maybe this solves the issue on a different level ;-)
回答3:
You aren't copying the temp file; you are just erasing your original file. I'm not sure why you aren't getting an error (you should be, because cp
expects two arguments).
Instead of
cp tmp.csh > $file
use
cp tmp.csv "$file"
来源:https://stackoverflow.com/questions/19981592/bash-oneliner-with-awk-runs-in-terminal-but-not-in-script