Crash on call from boost::python::exec( anything )

你。 提交于 2019-12-25 01:44:57

问题


I'm trying to implement some Python stuff into my program and I've decided to use Boost::Python, so I compiled it according to the instructions, with bjam, using mingw/gcc, getting dlls and .a files
I'm using Code::Blocks for this, so I've put the dlls in the working directory of my project, where the rest of dlls I use are, and decided to run boost::python::exec("b = 5");
Instantly I get a crash. Ideas?

#include <boost/python.hpp>

float func(int a)
{
  return a*a-0.5;
}

BOOST_PYTHON_MODULE(test_module)
{
  using namespace boost::python;
  def("func", func);
}

int main()
{
  //Try one
  boost::python::exec("b = 5");
  //Crash

  //Try two
  Py_Initialize();
  boost::python::exec("b = 5");
  //Works fine

  //Try three
  Py_Initialize();
  boost::python::exec("import test_module");
  //Throws boost::python::error_already_set and crashes

  /*
    Something along the lines of
    boost::python::exec("import test_module\n"
                        "var = test_module.func( 3 )\n");
  */    
}

Under the build options section of my project, I've added libboost_python3-mgw48-d-1_54.dll and libpython33 to be linked so it'd compile.
Ideas?


回答1:


When embedding Python, almost all calls to Python or Boost.Python should occur after the interpreter has been initialized with Py_Initialize(). Trying to invoke the interpreter before initialization, such as with boost::python::exec(), will result in undefined behavior.

While that identifies the source of the crash, there are some subtle details to obtain the accomplish the final goal of embedding Python and a module, then have exec import the embedded module.

  • When importing a module, Python will first check if the module is a built-in module. If the module is not a built-in module, then Python will try to load a library based on the module name, and expects the library to provide a function that will initialize the module. As the test_module is being embedded, its initialization needs to be explicitly added so that import can find it when searching for built-in modules.
  • The import statement uses the __import__ function. This function needs to be available within exec's globals.

Here is a complete example demonstrating how to accomplish this:

#include <boost/python.hpp>

float func(int a)
{
  return a*a-0.5;
}

BOOST_PYTHON_MODULE(test_module)
{
  using namespace boost::python;
  def("func", func);
}

// Use macros to account for changes in Python 2 and 3:
// - Python's C API for embedding requires different naming conventions for
//   module initialization functions.
// - The builtins module was renamed.
#if PY_VERSION_HEX >= 0x03000000
#  define MODULE_INIT_FN(name) BOOST_PP_CAT(PyInit_, name)
#  define PYTHON_BUILTINS "builtins"
#else
#  define MODULE_INIT_FN(name) BOOST_PP_CAT(init, name)
#  define PYTHON_BUILTINS "__builtin__"
#endif

int main()
{
  // Add the test_module module to the list of built-in modules.  This
  // allows it to be imported with 'import test_module'.
  PyImport_AppendInittab("test_module", &MODULE_INIT_FN(test_module));

  Py_Initialize();

  namespace python = boost::python;
  try
  {
    // Create an empty dictionary that will function as a namespace.
    python::dict ns;

    // The 'import' statement depends on the __import__ function.  Thus,
    // to enable 'import' to function the context of 'exec', the builtins
    // module needs to be within the namespace being used.
    ns["__builtins__"] = python::import(PYTHON_BUILTINS);

    // Execute code.  Modifications to variables will be reflected in
    // the ns.
    python::exec("b = 5", ns);

    std::cout << "b is " << python::extract<int>(ns["b"]) << std::endl;

    // Execute code using the built-in test_module.
    python::exec(
      "import test_module\n"
      "var = test_module.func(b)\n",
      ns);

    std::cout << "var is " << python::extract<float>(ns["var"]) << std::endl;
  }
  catch (python::error_already_set&)
  {
    PyErr_Print();
  }
}

When executed, its output is:

b is 5
var is 24.5


来源:https://stackoverflow.com/questions/19794760/crash-on-call-from-boostpythonexec-anything

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