问题
I would like to plot a sphere in R with the gridlines on the surface corresponding to the equal area gridding of the sphere using the arcos transformation.
I have been experimenting with the R packakge rgl and got some help from : Plot points on a sphere in R
Which plots the gridlines with equal lat long spacing.
I have the below function which returns a data frame of points that are the cross over points of the grid lines I want, but not sure how to proceed.
plot_sphere <- function(theta_num,phi_num){
theta <- seq(0,2*pi,(2*pi)/(theta_num))
phi <- seq(0,pi,pi/(phi_num))
tmp <- seq(0,2*phi_num,2)/phi_num
phi <- acos(1-tmp)
tmp <- cbind(rep(seq(1,theta_num),each = phi_num),rep(seq(1,phi_num),times = theta_num))
results <- as.data.frame(cbind(theta[tmp[,1]],phi[tmp[,2]]))
names(results) <- c("theta","phi")
results$x <- cos(results$theta)*sin(results$phi)
results$y <- sin(results$theta)*sin(results$phi)
results$z <- cos(results$phi)
return(results)
}
sphere <- plot_sphere(10,10)
Can anyone help, in general I am finding the rgl functions tricky to work with.
回答1:
If you use lines3d
or plot3d(..., type="l")
, you'll get a plot joining the points in your dataframe. To get breaks (you don't want one long line), add rows containing NA
values.
The code in your plot_sphere
function seems really messed up (you compute phi
twice, you don't generate vectors of the requested length, etc.), but this function based on it works:
function(theta_num,phi_num){
theta0 <- seq(0,2*pi, len = theta_num)
tmp <- seq(0, 2, len = phi_num)
phi0 <- acos(1-tmp)
i <- seq(1, (phi_num + 1)*theta_num) - 1
theta <- theta0[i %/% (phi_num + 1) + 1]
phi <- phi0[i %% (phi_num + 1) + 1]
i <- seq(1, phi_num*(theta_num + 1)) - 1
theta <- c(theta, theta0[i %% (theta_num + 1) + 1])
phi <- c(phi, phi0[i %/% (theta_num + 1) + 1])
results <- data.frame( x = cos(theta)*sin(phi),
y = sin(theta)*sin(phi),
z = cos(phi))
lines3d(results)
}
来源:https://stackoverflow.com/questions/54816367/plot-sphere-with-custom-gridlines-in-r