问题
Consider the following code:
class A(object):
def __init__(self):
print("A.__init__")
super(A, self).__init__() # 1
print("A.__init__ finished")
class B(A):
def __init__(self):
print("B.__init__")
super(B, self).__init__() # 2
print("B.__init__ finished")
class C(A):
def __init__(self):
print("C.__init__")
super(C, self).__init__()
print("C.__init__ finished")
class D(B, C):
def __init__(self):
print("D.__init__")
print("Initializing B")
B.__init__(self) # 3
print("B initialized")
print("Initializing C")
C.__init__(self) # 4
print("C initialized")
print("D.__init__ finished")
D()
# D.__init__
# Initializing B
# B.__init__
# C.__init__
# A.__init__
# A.__init__ finished
# C.__init__ finished
# B.__init__ finished
# B initialized
# Initializing C
# C.__init__
# A.__init__
# A.__init__ finished
# C.__init__ finished
# C initialized
# D.__init__ finished
As far as I understand, the algorithm is as follows:
D.__init__ at (3) -> B.__init__ ->
-> super().__init__ -> (super of self.__class__).__init__ ->
-> C.__init__ (# why C?) -> super().__init__ ->
-> A.__init__
D.__init__ at (4) -> C.__init__ ->
-> super().__init__ ->
-> A.__init__
Actually there are three questions:
1. Why super().__init__()
call in B.__init__
(at 2) calls C.__init__
when self
is an instance of D
?
2. How to avoid calling C.__init__
and A.__init__
twice in this case?
2.1 What is the right way to initialize all the classes the current class inherits from?
回答1:
Q: Why super().__init__()
call in B.__init__
(at 2) calls C.__init__
when self is an instance of D?
When you call
super(X, self).__init__
Python looks up the MRO self.__class__.mro()
. It then calls __init__
from the next class in the MRO after X.
When self is an instance of D
, self.__class__.mro()
is [D, B, C, A]
. So super(B, self).__init__()
calls C.__init__(self)
.
Q: What is the right way to initialize all the classes the current class inherits from?
Use super in D.__init__
as well:
class D(B, C):
def __init__(self):
print("D.__init__")
super(D, self).__init__()
print("D.__init__ finished")
来源:https://stackoverflow.com/questions/12457603/python-multiple-inheritance-avoid-calling-the-constructors-twice-in-diamond-sha