Recursion in a prime generator

问题

I'm making a prime generator, and to make it more efficient, i'm trying to only test numbers against primes that I've already found rather than all numbers < sqrt of the number being tested. I'm trying to get a to be my list of primes, but i'm not sure how to make it recur inside my second for loop. I think this is only testing against a <- 2 and not a <- c(a,i)

x <- 3:1000
a <- 2
for (i in x)
 {for (j in a)
  {if (i %% j == 0)
   {next}
  else {a <- unique(c(a,i))}}}
a

回答1:

A non-recursive mod using simple prime function that's about as fast as you can make it in R is below. Rather than cycle through each individual value and test it's primeness it removes all of the multiples of primes in big chunks. This isolates each subsequent remaining value as a prime. So, it takes out 2x, then 3x, then 4 is gone so 5x values go. It's the most efficient way to do it in R.

primest <- function(n){
    p <- 2:n
    i <- 1
    while (p[i] <= sqrt(n)) {
        p <-  p[p %% p[i] != 0 | p==p[i]]
        i <- i+1
    }
    p
}

(you might want to see this stack question for faster methods using a sieve and also my timings of the function. What's above will run 50, maybe 500x faster than the version you're working from.)

回答2:

The solution might be to cut out the second loop and instead compare your proposed prime number to the entire vector instead, like:

x <- 3:1000
a <- 2
for (i in x) {
  if (!any(i %% a == 0)) {
    a <- c(a,i)
  }
}

That seemed to work for me.

来源：https://stackoverflow.com/questions/3858636/recursion-in-a-prime-generator

标签

primes