问题
I have been trying to make a qpython program that uses sl4a.Android.recognizeSpeech
function. The functionality works fine online.
In my phone settings, I turned on and downloaded offline speech recognition and google now works fine offline, but the python speech does not work at all, asking me to try again every single time.
Sample Code:
import sl4a
import time
droid = sl4a.Android()
def speak(text):
droid.ttsSpeak(text)
while droid.ttsIsSpeaking()[1] == True:
time.sleep(1)
def listen():
return droid.recognizeSpeech('Speak Now',None,None)
def login():
speak('Passphrase, please')
try:
phrase = listen().result.lower()
except:
phrase = droid.dialogGetPassword('Passphrase').result
print(phrase)
if phrase == 'pork chops':
speak('Welcome')
else:
speak('Access Denied')
exit(0)
login()
回答1:
droid.recognizeSpeech("foo", None, None)
returns an Array with the recognized Speech in Index number 1. So if you want to access it, you have to type
return droid.recognizeSpeech("foo", None, None)[1]
回答2:
Actually none of the above worked for me. So I solved that this way:
x, result, error = droid.recognizeSpeech("Speak")
The result variable stores the speech recognized from the user
Example:
import sl4a
import time
droid = sl4a.Android()
def Speak(talk):
try:
droid.ttsSpeak(talk)
while droid.ttsIsSpeaking()[1] == True:
time.sleep(2)
except:
droid.ttsSpeak("nothing to say")
def listen():
global result,error
time.sleep(1)
x, result, error = droid.recognizeSpeech("Speak")
while True:
try:
listen()
except:
print(error)
try:
if len(str(result)) > 0:
print(result)
if result == "how old are you":
Speak("I'm 1 year old")
elif result is None:
break
else:
Speak("I heard " + result)
except Exception as e:
print(e)
break
来源:https://stackoverflow.com/questions/35683016/offline-speech-recognition-in-qpython3