问题
Signal driver_a is reassigned in the always block back to 0, but why is the always block not activating and assign value to driver_b ?
always @(driver_a) begin
driver_b = driver_a;
driver_a = 0;
end
initial begin
driver_a = 0; driver_b = 0;
#2 driver_a = 8'h8;
#2 driver_a = 8'hf;
end
In the waveform, I expect that after driver_a assigns its value to driver_b, then in the next line when driver_a gets assigned to 0, I'd expect the always block to reactivate and assign value 0 back to driver_b.
however this is not the case, the waveform seems to show that once the driver_a gets assigned to 0 in the always block, the always block does not reactivate and assign 0 back to driver_b's value. In short I'd expect driver_b's value to always remain 0, since code within an always block executes in zero simulation time.
I have attached the image of the resulting waveform, below
回答1:
Because the code is interpreted as single ordered set of statements. It's the same as if you had written
always begin
@(driver_a) // 1
driver_b = driver_a; // 2
driver_a = 0; // 3
end
Statement //1 means "Wait for driver_a to change" Statement //2 means "Change driver_b to the value of driver_a" Statement //3 means "Change driver_a to 0"
Because the always
block is a single thread that executes the statements in serial order, the change from //3 has already happened when it loops back to execute //1.
来源:https://stackoverflow.com/questions/54603171/why-always-block-not-reactivating-when-there-is-a-reassignment-of-logic-describe