问题
I have a data source where the dates come back like this: 20150614140520-0500
How can I display this better? It doesn't actually have to be converted technically, this is just for reporting. Ideally it would output 2015-06-14 2:05 PM (EST) but I also want the statement to be as simple as possible so the timezone offset and 12hr time are optional.
I tried CAST ('20150614140520-0500' As Date) but it returns null
I also tried CAST (LEFT('20150614140520-0500',14) As Date) as well as some other variants without luck.
回答1:
You have to take the first 14 characters, from the example above:
print convert(datetime,stuff(stuff(stuff(LEFT('20150614140520-0500',14) , 9, 0, ' '), 12, 0, ':'), 15, 0, ':'))
回答2:
Please try this:
convert(datetime,stuff(stuff(stuff(datevalue, 9, 0, ' '), 12, 0, ':'), 15, 0, ':')) ConvertedDate
As suggested by Dinesh Kumar Rajendran in his blog: https://rdineshkumar.wordpress.com/tag/how-to-convert-yyyymmddhhmmss-to-datetimedatetime-in-sql-server/
来源：https://stackoverflow.com/questions/30877285/how-can-i-reliably-convert-yyyymmddhhmmssoffset-to-a-date-time