问题
I want to plot a univariate normal density function of the normal distribution onto a (x,y,z) coordinate system. The code I am using is:
library(rgl)
open3d()
x <- seq(0, 10, length=100)
y <- seq(0, 10, length=100)
z = outer(x,y, function(x,y) dnorm(x,2.5,1)*dnorm(y,2.5,1))
persp3d(x, y, z,col = rainbow(100))
The problem I an encountering is that I want the normal distribution not to be around its mean only but also to be on a straight line or a circle. In latter case, I would expect the output to be similar to a volcano. I guess I must first create some probabilities within a loop. How can I do this? Or should I also use some surface command to plot the output? I am pretty sure this has nothing to do with a bivariate normal though.
Best Fuji
回答1:
The first part is easy: just don't let your z
depend on y
for instance:
z = outer(x,y, function(x,y) dnorm(x,2.5,1))
persp3d(x, y, z,col = rainbow(100))
For the second part, you can imagine that the means of the normal distribution lie on the x^2+y^2=1
circle. You will have infinite normal distributions with radial directions. Try this:
#define the volcano function
volcano<-function(x,y,sigma=1/2) {
alpha<-atan(y/x)+pi*(x<0)
d<-sqrt((cos(alpha)-x)^2 + (sin(alpha)-y)^2)
dnorm(d,0,sigma)
}
x<-seq(-2,2,length.out=100)
y<-seq(-2,2,length.out=100)
z<-outer(x,y,volcano)
persp3d(x, y, z,col = rainbow(100))
来源:https://stackoverflow.com/questions/36125313/3d-plot-of-normal-distribution-in-r-around-a-x-y-point