问题
I am using Laravel 5. In my OrganisationsController I have a method addItem
public function addItem(Request $request)
{
$rules = array(
'nom' => 'required',
);
// for Validator
$validator = Validator::make(Input::all(), $rules);
if ($validator->fails())
return Response::json(array('errors' => $validator->getMessageBag()->toArray()));
else {
$section = new Section();
$section->nom = $request->nom;
$section->save();
return response()->json($section);
}
}
Ajax code
$("#add").click(function() {
$.ajax({
type: 'post',
url: '/addItem',
data: {
'_token': $('input[name=_token]').val(),
'nom': $('input[name=nom]').val()
},
success: function(data) {
if ((data.errors)) {
$('.error').removeClass('hidden');
$('.error').text(data.errors.title);
$('.error').text(data.errors.description);
} else {
$('.error').remove()
$('table').append("<tr class='section" + data.id + "'><td>" + data.id + "</td><td>" + data.nom + "</td><td><button class='edit-modal btn btn-info' data-id='" + data.id + "' data-nom='" + data.nom + "'><span class='glyphicon glyphicon-edit'></span> Edit</button> <button class='delete-modal btn btn-danger' data-id='" + data.id + "' data-nom='" + data.nom + "'><span class='glyphicon glyphicon-trash'></span> Delete</button></td></tr>"); }
}
});
$('#noom').val('');
});
html code
<div class="form-group row add">
<div class="col-md-5">
<input type="text" class="form-control " id="noom" name="nom"
placeholder="New section here" required>
<p class="error text-center alert alert-danger hidden"></p>
</div>
<div class="col-md-2">
<button class="btn btn-warning" type="submit" id="add">
<span class="glyphicon glyphicon-plus"></span> Add new Section
</button>
</div>
</div>
I don't know why my validation not work. Please suggest a example for this. I am using laravel 5. I have searched so many sites. But I cannot get solution for this.
回答1:
If your validations fails it will return with a status code (error code) of 422
.
In your $.ajax
you're only using success
which won't be called if your validation fails.
You will need to add an error method to your ajax options. Using your above code you would have something like:
success: function (data) {
$('.error').remove()
$('table').append("<tr class='section" + data.id + "'><td>" + data.id + "</td><td>" + data.nom + "</td><td><button class='edit-modal btn btn-info' data-id='" + data.id + "' data-nom='" + data.nom + "'><span class='glyphicon glyphicon-edit'></span> Edit</button> <button class='delete-modal btn btn-danger' data-id='" + data.id + "' data-nom='" + data.nom + "'><span class='glyphicon glyphicon-trash'></span> Delete</button></td></tr>");
},
error: function (data) {
if (data.errors) {
$('.error').removeClass('hidden');
$('.error').text(data.errors.title);
$('.error').text(data.errors.description);
}
}
Hope this helps!
回答2:
the solution is remove the condition if(data.errors)
回答3:
for jquery 3 and above, use this code
$.ajax({
type: 'post',
url: '/addItem',
data: {
'_token': $('input[name=_token]').val(),
'nom': $('input[name=nom]').val()
}).done(function(data){
//if success, do this
console.log(data);
alert('success');
}).fail(function(jqXHR){
if (jqXHR.status == 422) {
var errors = (jqXHR.responseJSON);
console.log(errors);
}
});
来源:https://stackoverflow.com/questions/40422363/how-to-make-validation-using-ajax-laravel-5-3