问题
I want to fetch images from other site and display on my site. I want to store that images in my side temporary only at time of showing on page , so that user think images are coming from my site.is it possible? How? Thanks in advance.
ex:-
imagine there are some graphs generated in a server (some network monitoring graphs like smokeping )and those graphs are stored in a folder as .png
format.
ex:- imagine_this_url_has_a_graph (but this is just a page)
so that user want to show those graphs in another web site.
回答1:
A simple caching system would do this. Given an HTML file like:
<body>
<img src="imagesource.php?file=1" />
</body>
You could create your image data source (imagesource.php) like:
<?php
$files = array(
'http://somesite.com/image_to_cache.gif',
'http://somesite.com/image_to_cache2.gif'
);
if(!isset($_REQUEST['file']) || !isset($files[$_REQUEST['file']])) {
header('HTTP/1.0 404 Not Found');
exit;
}
// do we already have the cached file?
$requested_file = $files[$_REQUEST['file']];
$cache_dir = '/tmp/cached_images';
$cache_file = md5($requested_file);
$cache_path = $cache_dir . '/' . $cache_file;
header('Content-Type: image/gif');
if(file_exists($cache_path)) {
readfile($cache_path);
exit;
}
//need to create the cache.
$data = file_get_contents($requested_file);
file_put_contents($cache_path, $data);
echo $data;
This would cache the remote images locally if they haven't already been downloaded, and output them to the browser when requested.
回答2:
When the request for an image is made against your server, simply use fopen()
to open the remote image, and fpassthru()
to pass it through.
回答3:
use fileread()
instead of fopen()
if you want to output the image as it yours, otherwise, you will get an error.
来源:https://stackoverflow.com/questions/2069959/temporary-store-image-in-php-only-while-displaying-on-web-page