jq add capturing group result outside

问题

For example,

Input:

    {
       "id":"abc",
       "name": "name-middlenane-lastname-1"
    },

    {
        "id":"123",
        "name": "fname-flast-2"
    }

response:

    {
         "id":"abc",
         "name": "name-middlename-lastname-1",
         "newkey": "name-middlename-lastname"
    },

    {
          "id":"123",
          "name": "fname-flast-2",
          "newkey": "fname-flast"
    }

The filed name in each object is a string with characters and numbers separated by "-" hyphen. I need the complete string from beginning till the starting number. I don't want anything which is there after the number. And then the add new field with key as newkey and value should be extracted string without the number. Thus, the output should contain old fields as well as new one.

回答1:

jq solution:

Sample input.json:

[
  {
    "id": "abc",
    "name": "name-middlenane-lastname-1"
  },
  {
    "id": "123",
    "name": "fname-flast-2"
  }
]

---

jq 'map(. + (.name | capture("(?<newkey>.+)-[0-9]+")) )' input.json

The output:

[
  {
    "id": "abc",
    "name": "name-middlenane-lastname-1",
    "newkey": "name-middlenane-lastname"
  },
  {
    "id": "123",
    "name": "fname-flast-2",
    "newkey": "fname-flast"
  }
]

来源：https://stackoverflow.com/questions/49553691/jq-add-capturing-group-result-outside