问题
I'm working to make client rest service with jasperserver to generate reports. I'm using the following code to make that:
I have problem in setting server url and report path,
for server url I put http://localhost:8081/jasperserver/
and as shown in next image I put report path rest/report/mytest/my_report
but I get 404 not found error in line
File remoteFile = resource.get(File.class);
So how can I get the proper report path from jasperserver?
public class App2 {
private final static String serverUrl = "http://localhost:8081
/jasperserver/";
private final static String serverUser = "jasperadmin";
private final static String serverPassword = "jasperadmin";
public static void main(String arg[]) throws Exception {
Report reporte = new Report();
reporte.setFormat("pdf");
reporte.setOutputFolder("/home/ali/images");
ClientConfig clientConfig;
Map<String, String> resourceCache=new HashMap<String, String>();
clientConfig = new DefaultApacheHttpClientConfig();
clientConfig.getProperties().put(ClientConfig.PROPERTY_FOLLOW_REDIRECTS, true);
clientConfig.getProperties().put(ApacheHttpClientConfig.PROPERTY_HANDLE_COOKIES, true);
ApacheHttpClient client = ApacheHttpClient.create(clientConfig);
client.addFilter(new HTTPBasicAuthFilter(serverUser, serverPassword));
String describeResourcePath = "/rest/resource" + "/mytest/my_report/";
String generateReportPath = "/rest/report" + "/mytest/my_report/" + "?RUN_OUTPUT_FORMAT=" + reporte.getFormat();
WebResource resource = null;
String resourceResponse = null;
if (resourceCache.containsKey(describeResourcePath)) {
resourceResponse = resourceCache.get(describeResourcePath);
} else {
resource = client.resource(serverUrl);
resource.accept(MediaType.APPLICATION_XML);
resourceResponse = resource.path(describeResourcePath).get(String.class);
resourceCache.put(describeResourcePath, resourceResponse);
}
Document resourceXML = parseResource(resourceResponse);
resourceXML = addParametersToResource(resourceXML, reporte);
resource = client.resource(serverUrl + generateReportPath);
resource.accept(MediaType.TEXT_XML);
System.out.println(resource);
String reportResponse = resource.put(String.class, serializetoXML(resourceXML));
String urlReport = parseReport(reportResponse);
resource = client.resource(urlReport);
System.out.println(resource);
File destFile = null;
try {
File remoteFile = resource.get(File.class);
File parentDir = new File(reporte.getOutputFolder());
destFile = File.createTempFile("report_", "." + getExtension(reporte.getFormat()), parentDir);
FileUtils.copyFile(remoteFile, destFile);
} catch (IOException e) {
throw e;
}
}
/**
*
* @return
* @throws DocumentException
*/
private static Document parseResource(String resourceAsText) throws Exception {
// LOGGER.debug("parseResource:\n" + resourceAsText);
Document document;
try {
document = DocumentHelper.parseText(resourceAsText);
} catch (DocumentException e) {
throw e;
}
return document;
}
/**
*
*/
private static String parseReport(String reportResponse) throws Exception {
String urlReport = null;
try {
Document document = DocumentHelper.parseText(reportResponse);
Node node = document.selectSingleNode("/report/uuid");
String uuid = node.getText();
node = document.selectSingleNode("/report/totalPages");
Integer totalPages = Integer.parseInt(node.getText());
if (totalPages == 0) {
throw new Exception("Error generando reporte");
}
urlReport = serverUrl + "/report/" + uuid + "?file=report";
} catch (DocumentException e) {
throw e;
}
return urlReport;
}
/**
*
* @param resource
* @param reporte
* @return
*/
private static Document addParametersToResource(Document resource, Report reporte) {
// LOGGER.debug("addParametersToResource");
Element root = resource.getRootElement();
Map<String, String> params = reporte.getParams();
for (Map.Entry<String, String> entry : params.entrySet()) {
String key = entry.getKey();
String value = entry.getValue();
if (key != null && value != null) {
root.addElement("parameter").addAttribute("name", key).addText(value);
}
}
// LOGGER.debug("resource:" + resource.asXML());
return resource;
}
/**
*
* @param aEncodingScheme
* @throws IOException
* @throws Exception
*/
private static String serializetoXML(Document resource) throws Exception {
OutputFormat outformat = OutputFormat.createCompactFormat();
ByteArrayOutputStream out = new ByteArrayOutputStream();
outformat.setEncoding("ISO-8859-1");
try {
XMLWriter writer = new XMLWriter(out, outformat);
writer.write(resource);
writer.flush();
} catch (IOException e) {
throw e;
}
return out.toString();
}
/**
*
* @param format
* @return
*/
private static String getExtension(String format) {
String ext = null;
if (format.equals(Report.FORMAT_PDF)) {
ext = "pdf";
} else if (format.equals(Report.FORMAT_EXCEL)) {
ext = "xls";
}
return ext;
}
}
回答1:
I have fixed it,I need to change path
urlReport = serverUrl + "/report/" + uuid + "?file=report";
to
urlReport = serverUrl + "/rest/report/" + uuid + "?file=report";
in parseReport method
private static String parseReport(String reportResponse) throws Exception {
String urlReport = null;
try {
Document document = DocumentHelper.parseText(reportResponse);
Node node = document.selectSingleNode("/report/uuid");
String uuid = node.getText();
node = document.selectSingleNode("/report/totalPages");
Integer totalPages = Integer.parseInt(node.getText());
if (totalPages == 0) {
throw new Exception("Error generando reporte");
}
urlReport = serverUrl + "/report/" + uuid + "?file=report";
} catch (DocumentException e) {
throw e;
}
return urlReport;
}
来源:https://stackoverflow.com/questions/37509433/how-is-the-jasperserver-rest-client-path