问题
This is an example document of my mongoDB. I need to get the content.en
array via Apollo/GraphQL. But the nested object is getting a problem for me.
en
is the language tag, so it would be great if this could be used as a variable.
Data in MongoDB
{
"_id" : "9uPjYoYu58WM5Tbtf",
"content" : {
"en" : [
{
"content" : "Third paragraph",
"timestamp" : 1484939404
}
]
},
"main" : "Dn59y87PGhkJXpaiZ"
}
The graphQL result should be:
{
"data": {
"article": [
{
"_id": "9uPjYoYu58WM5Tbtf",
"content": [
{
"content" : "Third paragraph",
"timestamp" : 1484939404
}
]
}
]
}
}
That means, I need to get the ID and the language specific content array.
But this is not, what I'm getting with the following setup:
Type
const ArticleType = new GraphQLObjectType({
name: 'article',
fields: {
_id: { type: GraphQLID },
content: { type: GraphQLString }
}
})
GraphQL Schema
export default new GraphQLSchema({
query: new GraphQLObjectType({
name: 'RootQueryType',
fields: {
article: {
type: new GraphQLList(ArticleType),
description: 'Content of article dataset',
args: {
id: {
name: 'id',
type: new GraphQLNonNull(GraphQLID)
}
},
async resolve ({ db }, args) {
return db.collection('articles').find({ main: args.id }).toArray()
}
}
}
})
})
Query
{
article(id: "Dn59y87PGhkJXpaiZ") {
_id,
content
}
}
Result
{
"data": {
"article": [
{
"_id": "9uPjYoYu58WM5Tbtf",
"content": "[object Object]"
}
]
}
}
回答1:
You can use below code.
String query = {
article(id: "Dn59y87PGhkJXpaiZ") {
_id,
content(language:"en") {
content,
timestamp
}
}
}
const ContentType = new GraphQLObjectType({
name: 'content',
fields: {
content: { type: GraphQLString },
timestamp: { type: GraphQLInt }
}
})
const ArticleType = new GraphQLObjectType({
name: 'article',
fields: {
_id: { type: GraphQLID },
content: {
type: new GraphQLList(ContentType),
args: {
language: {
name: 'language',
type: new GraphQLNonNull(GraphQLString)
}
},
async resolve (args) {
return filter content here by lang
}
}
}
}
})
export default new GraphQLSchema({
query: new GraphQLObjectType({
name: 'RootQueryType',
fields: {
article: {
type: new GraphQLList(ArticleType),
description: 'Content of article dataset',
args: {
id: {
name: 'id',
type: new GraphQLNonNull(GraphQLID)
}
},
async resolve ({ db }, args) {
return db.collection('articles').find({ main: args.id}).toArray()
}
}
}
})
})
Java Example:
import com.mongodb.MongoClient;
import com.mongodb.client.MongoCollection;
import com.mongodb.client.MongoDatabase;
import com.mongodb.client.model.Filters;
import graphql.ExecutionResult;
import graphql.GraphQL;
import graphql.schema.*;
import org.bson.Document;
import java.util.ArrayList;
import java.util.List;
import java.util.Map;
import static graphql.Scalars.*;
import static graphql.schema.GraphQLArgument.newArgument;
import static graphql.schema.GraphQLFieldDefinition.newFieldDefinition;
import static graphql.schema.GraphQLObjectType.newObject;
import static graphql.schema.GraphQLSchema.newSchema;
public class GraphQLTest {
private static final ArticleRepository articleRepository;
public static class ArticleRepository {
private final MongoCollection<Document> articles;
ArticleRepository(MongoCollection<Document> articles) {
this.articles = articles;
}
public List<Map<String, Object>> getAllArticles(String id) {
List<Map<String, Object>> allArticles = articles.find(Filters.eq("main", id)).map(doc -> (Map<String, Object>)doc).into(new ArrayList<>());
return allArticles;
}
}
public static void main(String... args) {
String query = "{\n" +
" article(id: \"Dn59y87PGhkJXpaiZ\") {\n" +
" _id,\n" +
" content(language:\"en\") {\n" +
" content,\n" +
" timestamp\n" +
" }\n" +
" }\n" +
"}";
ExecutionResult result = GraphQL.newGraphQL(buildSchema()).build().execute(query);
System.out.print(result.getData().toString());
}
static {
MongoDatabase mongo = new MongoClient().getDatabase("test");
articleRepository = new ArticleRepository(mongo.getCollection("articles"));
}
private static GraphQLSchema buildSchema() {
GraphQLObjectType ContentType = newObject().name("content")
.field(newFieldDefinition().name("content").type(GraphQLString).build())
.field(newFieldDefinition().name("timestamp").type(GraphQLInt).build()).build();
GraphQLObjectType ArticleType = newObject().name("article")
.field(newFieldDefinition().name("_id").type(GraphQLID).build())
.field(newFieldDefinition().name("content").type(new GraphQLList(ContentType))
.argument(newArgument().name("language").type(GraphQLString).build())
.dataFetcher(dataFetchingEnvironment -> {
Document source = dataFetchingEnvironment.getSource();
Document contentMap = (Document) source.get("content");
ArrayList<Document> contents = (ArrayList<Document>) contentMap.get(dataFetchingEnvironment.getArgument("lang"));
return contents;
}).build()).build();
GraphQLFieldDefinition.Builder articleDefinition = newFieldDefinition()
.name("article")
.type(new GraphQLList(ArticleType))
.argument(newArgument().name("id").type(new GraphQLNonNull(GraphQLID)).build())
.dataFetcher(dataFetchingEnvironment -> articleRepository.getAllArticles(dataFetchingEnvironment.getArgument("id")));
return newSchema().query(
newObject()
.name("RootQueryType")
.field(articleDefinition)
.build()
).build();
}
}
回答2:
I think the problem comes from this line:
content: { type: GraphQLString }
. Try extracting content to another GraphQLObjectType
and then pass it to ArticleType
as content
field
Edit
Try this:
const ContentType = new GraphQLObjectType({
name: 'content',
fields: {
en: { type: GraphQLList },
it: { type: GraphQLList }
// ... other languages
}
})
回答3:
Since you said that the language ISO code should be a parameter and that the content is depending on a language ISO code (I'll call it languageTag
from now on), I figured that you should edit your schema to look something like this:
export default new GraphQLSchema({
query: new GraphQLObjectType({
name: 'RootQueryType',
fields: {
article: {
type: new GraphQLList(ArticleType),
description: 'Content of article dataset',
args: {
id: {
name: 'id',
type: new GraphQLNonNull(GraphQLID)
},
// Edited this part to add the language tag
languageTag: {
name: 'languageTag',
type: new GraphQLNonNull(GraphQLString)
}
},
async resolve ({ db }, args) {
return db.collection('articles').find({ main: args.id }).toArray()
}
}
}
})
})
However, this still does not fix your issue of retrieving the content. I reckon that you need to add another type to your schema called ContentType
.
const ContentType = new GraphQLObjectType({
name: 'ContentType',
fields: {
content: {
type: GraphQLString,
resolve: (root, args, context) => root.content[args.languageTag].content
},
timestamp: {
type: GraphQLString,
resolve: (root, args, context) => root.content[args.languageTag].timestamp
}
},
})
One final issue I would like to bring up is that you are returning a single article
as an Array
. I would suggest to change this to return a single object. Last but not least, your schema would look something like this:
export default new GraphQLSchema({
query: new GraphQLObjectType({
name: 'RootQueryType',
fields: {
article: {
type: new GraphQLList(ArticleType),
description: 'Content of article dataset',
args: {
id: {
name: 'id',
type: new GraphQLNonNull(GraphQLID)
},
// Edited this part to add the language tag
languageTag: {
name: 'languageTag',
type: new GraphQLNonNull(GraphQLString)
},
// Add the extra fields to the article
fields: {
content: ContentType
}
async resolve ({ db }, args) {
return db.collection('articles').findOne({ main: args.id })
}
}
}
})
})
This code could be a little bit off, since I do not have your database to test it. I think that it is a good push in the right direction.
来源:https://stackoverflow.com/questions/46935272/apollo-graphql-how-to-get-nested-elements